There are 7 atoms in one formula unit of magnesium phosphate (Mg3(PO4)2: 3 magnesium atoms, 2 phosphorus atoms, and 8 oxygen atoms.
To calculate the number of atoms in 4Ca3(PO4)2, break down the formula: 4 molecules of Ca3(PO4)2 has 4 * 3 * (1 + 4 + 8) = 4 * 3 * 13 = 156 atoms.
To determine the number of atoms in 2 Sr3(PO4)2, we first need to break down the chemical formula. Sr3(PO4)2 consists of 3 strontium (Sr) atoms, 2 phosphate (PO4) groups, each containing 1 phosphorus (P) atom and 4 oxygen (O) atoms. Multiplying these by 2 gives us a total of 6 Sr atoms, 2 P atoms, and 16 O atoms in one molecule of Sr3(PO4)2. Therefore, in 2 molecules of Sr3(PO4)2, there are 12 Sr atoms, 4 P atoms, and 32 O atoms.
There is more than one compound between magnesium and phosphate, but the most common one has a formula of Mg3(PO4)2. This formula unit contains 13 atoms: 3 of magnesium, 2 of phosphorus, and 8 of oxygen.
Mg(oh)2 contains of Mg,O and h atoms. There are 3 atoms in 1 Mg(OH)2. So there are 12 atoms in 4Mg(OH)2.
There are 9 atoms present in one molecule of Mg(NO3)2.
In the compound Mg3(PO4)2, there are 3 magnesium (Mg) atoms, 2 phosphorus (P) atoms, and 8 oxygen (O) atoms (since each phosphate group, PO4, contains 4 oxygen atoms and there are 2 phosphate groups). To find the total number of atoms, you add these together: 3 (Mg) + 2 (P) + 8 (O) = 13 atoms in total.
Ca3(PO4)2 has a total of 13 atoms.
In the chemical formula Mg3(PO4)2, there are a total of 13 atoms. This consists of 3 magnesium (Mg) atoms, 2 phosphorus (P) atoms, and 8 oxygen (O) atoms (since each phosphate group, PO4, contains 4 oxygen atoms and there are 2 phosphate groups). Thus, the breakdown is 3 + 2 + 8 = 13 atoms in total.
How many atoms are in Mg3(PO4)2
Ca3 (PO4)2 has 13 atoms in the molecule.
Ca3 (PO4)2 has 13 atoms in the molecule.
To calculate the number of atoms in 4Ca3(PO4)2, break down the formula: 4 molecules of Ca3(PO4)2 has 4 * 3 * (1 + 4 + 8) = 4 * 3 * 13 = 156 atoms.
To find the number of atoms in 2Sr3(PO4)2, first, we determine the composition of one formula unit of Sr3(PO4)2. It contains 3 strontium (Sr) atoms, 2 phosphorus (P) atoms, and 8 oxygen (O) atoms (since there are 4 oxygen atoms in each phosphate group and there are 2 phosphate groups). Therefore, one unit has a total of 3 + 2 + 8 = 13 atoms. Multiplying by 2 gives 2 × 13 = 26 atoms in 2Sr3(PO4)2.
To determine the number of atoms in 2 Sr3(PO4)2, we first need to break down the chemical formula. Sr3(PO4)2 consists of 3 strontium (Sr) atoms, 2 phosphate (PO4) groups, each containing 1 phosphorus (P) atom and 4 oxygen (O) atoms. Multiplying these by 2 gives us a total of 6 Sr atoms, 2 P atoms, and 16 O atoms in one molecule of Sr3(PO4)2. Therefore, in 2 molecules of Sr3(PO4)2, there are 12 Sr atoms, 4 P atoms, and 32 O atoms.
There is more than one compound between magnesium and phosphate, but the most common one has a formula of Mg3(PO4)2. This formula unit contains 13 atoms: 3 of magnesium, 2 of phosphorus, and 8 of oxygen.
Ca3(PO4 )2 That is 3+(2(2)+4(2)) = 15 so, 15 atoms
In the compound Sr3(PO4)2, there are a total of 17 atoms. This is calculated by noting that there are 3 strontium (Sr) atoms, 2 phosphate (PO4) groups, each containing 1 phosphorus (P) atom and 4 oxygen (O) atoms. Therefore, the total is 3 Sr + 2 P + (2 × 4 O) = 3 + 2 + 8 = 13 atoms.