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How many atoms are in 4Ca3(PO4)2?
To calculate the number of atoms in 4Ca3(PO4)2, break down the formula: 4 molecules of Ca3(PO4)2 has 4 * 3 * (1 + 4 + 8) = 4 * 3 * 13 = 156 atoms.
How many atoms are in 2 Sr3(PO4)2?
To determine the number of atoms in 2 Sr3(PO4)2, we first need to break down the chemical formula. Sr3(PO4)2 consists of 3 strontium (Sr) atoms, 2 phosphate (PO4) groups, each containing 1 phosphorus (P) atom and 4 oxygen (O) atoms. Multiplying these by 2 gives us a total of 6 Sr atoms, 2 P atoms, and 16 O atoms in one molecule of Sr3(PO4)2. Therefore, in 2 molecules of Sr3(PO4)2, there are 12 Sr atoms, 4 P atoms, and 32 O atoms.
How many atoms of each element are in a compound made from magnesium and phosphate?
There is more than one compound between magnesium and phosphate, but the most common one has a formula of Mg3(PO4)2. This formula unit contains 13 atoms: 3 of magnesium, 2 of phosphorus, and 8 of oxygen.
How many atoms are in 4 Mg OH2?
Mg(oh)2 contains of Mg,O and h atoms. There are 3 atoms in 1 Mg(OH)2. So there are 12 atoms in 4Mg(OH)2.
HOW MANY ATOMS ARE IN Mg (NO3)2?
There are 9 atoms present in one molecule of Mg(NO3)2.
How many atoms in Mg3(PO4)2?
In the compound Mg3(PO4)2, there are 3 magnesium (Mg) atoms, 2 phosphorus (P) atoms, and 8 oxygen (O) atoms (since each phosphate group, PO4, contains 4 oxygen atoms and there are 2 phosphate groups). To find the total number of atoms, you add these together: 3 (Mg) + 2 (P) + 8 (O) = 13 atoms in total.
How many atoms does ca3(po4)2 have?
Ca3(PO4)2 has a total of 13 atoms.
How many atoms are in Mg3(PO4)2?
In the chemical formula Mg3(PO4)2, there are a total of 13 atoms. This consists of 3 magnesium (Mg) atoms, 2 phosphorus (P) atoms, and 8 oxygen (O) atoms (since each phosphate group, PO4, contains 4 oxygen atoms and there are 2 phosphate groups). Thus, the breakdown is 3 + 2 + 8 = 13 atoms in total.
Counting the numbers of atoms of each element in Mg3(PO4)2?
How many atoms are in Mg3(PO4)2
How many atoms are present in Ca3P2?
Ca3 (PO4)2 has 13 atoms in the molecule.
How many atoms are in ca3 po4 2?
Ca3 (PO4)2 has 13 atoms in the molecule.
How many atoms are in 4Ca3(PO4)2?
To calculate the number of atoms in 4Ca3(PO4)2, break down the formula: 4 molecules of Ca3(PO4)2 has 4 * 3 * (1 + 4 + 8) = 4 * 3 * 13 = 156 atoms.
How many atoms in 2Sr3(PO4)2?
To find the number of atoms in 2Sr3(PO4)2, first, we determine the composition of one formula unit of Sr3(PO4)2. It contains 3 strontium (Sr) atoms, 2 phosphorus (P) atoms, and 8 oxygen (O) atoms (since there are 4 oxygen atoms in each phosphate group and there are 2 phosphate groups). Therefore, one unit has a total of 3 + 2 + 8 = 13 atoms. Multiplying by 2 gives 2 × 13 = 26 atoms in 2Sr3(PO4)2.
How many atoms are in 2 Sr3(PO4)2?
To determine the number of atoms in 2 Sr3(PO4)2, we first need to break down the chemical formula. Sr3(PO4)2 consists of 3 strontium (Sr) atoms, 2 phosphate (PO4) groups, each containing 1 phosphorus (P) atom and 4 oxygen (O) atoms. Multiplying these by 2 gives us a total of 6 Sr atoms, 2 P atoms, and 16 O atoms in one molecule of Sr3(PO4)2. Therefore, in 2 molecules of Sr3(PO4)2, there are 12 Sr atoms, 4 P atoms, and 32 O atoms.
How many atoms of each element are in a compound made from magnesium and phosphate?
There is more than one compound between magnesium and phosphate, but the most common one has a formula of Mg3(PO4)2. This formula unit contains 13 atoms: 3 of magnesium, 2 of phosphorus, and 8 of oxygen.
How many atoms are in Ca3PO4 2?
Ca3(PO4 )2 That is 3+(2(2)+4(2)) = 15 so, 15 atoms
How many atoms are in the compound Sr3(PO4)2?
In the compound Sr3(PO4)2, there are a total of 17 atoms. This is calculated by noting that there are 3 strontium (Sr) atoms, 2 phosphate (PO4) groups, each containing 1 phosphorus (P) atom and 4 oxygen (O) atoms. Therefore, the total is 3 Sr + 2 P + (2 × 4 O) = 3 + 2 + 8 = 13 atoms.
