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For this problem you don't need the Atomic Mass of the element. If you want to convert moles to atoms, you need to take the number of moles and multiply it by Avogadro's constant, 6.02 Ã— 1023. Divide by one mole for units to cancel.

2.50 moles H Ã— (6.02 Ã— 1023 atoms) = 1.51 Ã—1024 atoms H

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If you mean in 2.5 moles of the element H, then it will be 2.5 moles H x 6.02x10^23 atoms/mole = 1.5x10^24 atoms. If you mean 2.50 moles of hydrogen gas (H2), then it will be twice that or 3x10^24 atoms.

2.5 mol of uranium = 2,5 x Avogadro's number = 15,055354475.1023 atoms

1 mole atoms U = 6.022 x 1023 atoms

2.50mol U x 6.022 x 1023 atoms/1mol = 1.51 x 1024 atoms U

2.50 mole of H2 contains 5.0 moles of hydrogen atoms (H),

which are 5.0 * 6.02*10+23 atoms (particles) = 3.0*1024 atoms H

2.5 moles Ã— (6.02 Ã— 1023) = 1.51 Ã— 1024 atoms

15,055354475.1023 uranium atoms

If 2,5 is grams: 6,325.1021 atoms.

Q: How many atoms are there in 2.50 mol of hydrogen?

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338.10e23 hydrogen atoms

The answer is 175,08.10e23 atoms.

there are 1.30e25 Hydrogen atoms in 2.70 mol Ammonium Sulfide

The conversion. 4 mol C5H10 ( 10 mol H/1 mol C5H10 ) = 40 mol Hydrogen.

360 g H2O x 1 mol/18g H2O x 6.02x10^23 H2O molecules/mol x 2 H atoms/molecule = 2.4x10^25 hydrogen atoms.

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338.10e23 hydrogen atoms

0.63 mol of (NH4)2SO4 contain 3,978.10e23 hydrogen atoms.

Avagadro's number = 6.022 × 1023 atoms/mol0.5 mol × (6.022 × 1023) atoms/mol = 3.011 ×1023 atoms

The answer is 175,08.10e23 atoms.

there are 1.30e25 Hydrogen atoms in 2.70 mol Ammonium Sulfide

there are 1.30e25 Hydrogen atoms in 2.70 mol Ammonium Sulfide

1 molecule of hydrogen contains 2 hydrogen atoms,so 1 mole of hydrogen consists of 2 moles of atoms.

1.64 x 1025

The conversion. 4 mol C5H10 ( 10 mol H/1 mol C5H10 ) = 40 mol Hydrogen.

360 g H2O x 1 mol/18g H2O x 6.02x10^23 H2O molecules/mol x 2 H atoms/molecule = 2.4x10^25 hydrogen atoms.

The molar mass of hydrogen is 2.01588 g/mol Avogadro's number is 6.022141 x 1023 molecules/mol 2.99 picograms * 1mol/2.01588 grams * 1x10-12 g/pg * 6.022141x1023 molecules/mol * 2 atoms/molecule = 1.79x1012 atoms

1 mole NH3 (3 mole H/1 mole NH3) = 3 mole hydrogen atoms