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First divide 88.9 by 16.Then multiply it by 6.022x10^23.Then mutiply answer by five

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How many hydrogen atoms are there in 3.50 grams of methane?

3.5 g CH4 x 1 mole/16 g x 6.02x10^23 molecules/mole x 4 H atoms/molecule = answer.


How many atoms are there in 64.5 grams of methane?

Molecular mass of CH4 = 12.0 + 4(1.0) = 16.0 Amount of CH4 = 64.5/16.0 = 4.03mol 1mol of CH4 contains 6.02 x 1023 molecules (avogadro constant). Therefore 4.03mol of CH4 contains 4.03 x 6.02 x 1023 = 2.43 x 1024 molecules.


How many grams of CO2 are formed for every gram of CH4 that combusts?

The balanced equation for combustion of CH4 is CH4 + 2O2 ==> CO2 + 2H2OThus, one mole CH4 produces 1 mole CO21 g CH4 x 1 mole CH4/16 g = 0.0625 moles CH40.0625 moles CH4 ==> 0.0625 moles CO20.0625 moles CO2 x 44 g CO2/mole = 2.75 g CO2Thus, the answer would be that 1 grams of CH4 will produce 2.75 grams of CO2 after complete combustion.


How many mole of CH4 are in 96.0 grams of CH4?

Divide 96 by molecular mass.So the answer is 6mol


When 85.0 g of CH4 are mixed with 160 g of O2 the limiting reactant is?

When 85.0 g of CH4 are mixed with 160. g of O2 the limiting reactant is __________. CH4 + 2O2 → CO2 + 2H2O


How many atoms of carbon is in methane and molecular mass?

Methane (CH4) contains 1 carbon atom. The molecular mass of methane is approximately 16 g/mol.


How many moles of CH4 are in 200 grams of CH4?

200 g CH4 x 1 mole CH4/16 g = 12.5 moles CH4


How many atoms in 16 gram of CH4?

CH4 has a molecular weight of 16, which makes the math easy. Each mole of carbon has a weight of 12. Each carbon binds with 2 oxygen to make CO2. The oxygen weighs 16. CO2 weighs 12+2*16=44 grams. Each mole of hydrogen weighs 1 g. 2 Hydrogens bind with 1 oxygen to make H2O, which has a weight of 18g. There are 4 hydrogen atoms available so we make 2 water molecules with a total weight of 36g. The total mass of products of combustion for 16 g of methane is about 80 g.


How many moles of methane are required to produce 22g of CO2?

The balanced chemical equation for the combustion of methane is CH4 + 2O2 -> CO2 + 2H2O. This means that for every mole of CH4 that reacts, one mole of CO2 is produced. The molar mass of CO2 is about 44g/mol, so 22g CO2 is equivalent to 0.5 moles. Therefore, 0.5 moles of CH4 are required to produce 22g of CO2.


How many moles of CH4 are present in 6.07 g of (CH4)?

Divide 96 by molecular mass.So the answer is 6mol


How many atoms are in 49.1740 g of zirconium?

49.1740 g (6.02 x 1023 atoms) / (91.22 g) = 3.25 x 1023 atoms


Why does methane undergo oxidation?

Methane , CH4 , is a fuel that can react with O2 to yield CO2, H2O, and heat. CH4 (g) + O2 (g) ----> CO2 (g) + 2 H2O (g) + Heat