First divide 88.9 by 16.Then multiply it by 6.022x10^23.Then mutiply answer by five
Molecular mass of CH4 = 12.0 + 4(1.0) = 16.0 Amount of CH4 = 64.5/16.0 = 4.03mol 1mol of CH4 contains 6.02 x 1023 molecules (avogadro constant). Therefore 4.03mol of CH4 contains 4.03 x 6.02 x 1023 = 2.43 x 1024 molecules.
Divide 96 by molecular mass.So the answer is 6mol
200 g CH4 x 1 mole CH4/16 g = 12.5 moles CH4
The balanced chemical equation for the combustion of methane is CH4 + 2O2 -> CO2 + 2H2O. This means that for every mole of CH4 that reacts, one mole of CO2 is produced. The molar mass of CO2 is about 44g/mol, so 22g CO2 is equivalent to 0.5 moles. Therefore, 0.5 moles of CH4 are required to produce 22g of CO2.
Divide 96 by molecular mass.So the answer is 6mol
3.5 g CH4 x 1 mole/16 g x 6.02x10^23 molecules/mole x 4 H atoms/molecule = answer.
Molecular mass of CH4 = 12.0 + 4(1.0) = 16.0 Amount of CH4 = 64.5/16.0 = 4.03mol 1mol of CH4 contains 6.02 x 1023 molecules (avogadro constant). Therefore 4.03mol of CH4 contains 4.03 x 6.02 x 1023 = 2.43 x 1024 molecules.
The balanced equation for combustion of CH4 is CH4 + 2O2 ==> CO2 + 2H2OThus, one mole CH4 produces 1 mole CO21 g CH4 x 1 mole CH4/16 g = 0.0625 moles CH40.0625 moles CH4 ==> 0.0625 moles CO20.0625 moles CO2 x 44 g CO2/mole = 2.75 g CO2Thus, the answer would be that 1 grams of CH4 will produce 2.75 grams of CO2 after complete combustion.
Divide 96 by molecular mass.So the answer is 6mol
When 85.0 g of CH4 are mixed with 160. g of O2 the limiting reactant is __________. CH4 + 2O2 → CO2 + 2H2O
Methane (CH4) contains 1 carbon atom. The molecular mass of methane is approximately 16 g/mol.
200 g CH4 x 1 mole CH4/16 g = 12.5 moles CH4
CH4 has a molecular weight of 16, which makes the math easy. Each mole of carbon has a weight of 12. Each carbon binds with 2 oxygen to make CO2. The oxygen weighs 16. CO2 weighs 12+2*16=44 grams. Each mole of hydrogen weighs 1 g. 2 Hydrogens bind with 1 oxygen to make H2O, which has a weight of 18g. There are 4 hydrogen atoms available so we make 2 water molecules with a total weight of 36g. The total mass of products of combustion for 16 g of methane is about 80 g.
The balanced chemical equation for the combustion of methane is CH4 + 2O2 -> CO2 + 2H2O. This means that for every mole of CH4 that reacts, one mole of CO2 is produced. The molar mass of CO2 is about 44g/mol, so 22g CO2 is equivalent to 0.5 moles. Therefore, 0.5 moles of CH4 are required to produce 22g of CO2.
Divide 96 by molecular mass.So the answer is 6mol
49.1740 g (6.02 x 1023 atoms) / (91.22 g) = 3.25 x 1023 atoms
Methane , CH4 , is a fuel that can react with O2 to yield CO2, H2O, and heat. CH4 (g) + O2 (g) ----> CO2 (g) + 2 H2O (g) + Heat