First divide 88.9 by 16.Then multiply it by 6.022x10^23.Then mutiply answer by five
Molecular mass of CH4 = 12.0 + 4(1.0) = 16.0 Amount of CH4 = 64.5/16.0 = 4.03mol 1mol of CH4 contains 6.02 x 1023 molecules (avogadro constant). Therefore 4.03mol of CH4 contains 4.03 x 6.02 x 1023 = 2.43 x 1024 molecules.
Divide 96 by molecular mass.So the answer is 6mol
200 g CH4 x 1 mole CH4/16 g = 12.5 moles CH4
The balanced chemical equation for the combustion of methane is CH4 + 2O2 -> CO2 + 2H2O. This means that for every mole of CH4 that reacts, one mole of CO2 is produced. The molar mass of CO2 is about 44g/mol, so 22g CO2 is equivalent to 0.5 moles. Therefore, 0.5 moles of CH4 are required to produce 22g of CO2.
Divide 96 by molecular mass.So the answer is 6mol
3.5 g CH4 x 1 mole/16 g x 6.02x10^23 molecules/mole x 4 H atoms/molecule = answer.
Molecular mass of CH4 = 12.0 + 4(1.0) = 16.0 Amount of CH4 = 64.5/16.0 = 4.03mol 1mol of CH4 contains 6.02 x 1023 molecules (avogadro constant). Therefore 4.03mol of CH4 contains 4.03 x 6.02 x 1023 = 2.43 x 1024 molecules.
The balanced equation for combustion of CH4 is CH4 + 2O2 ==> CO2 + 2H2OThus, one mole CH4 produces 1 mole CO21 g CH4 x 1 mole CH4/16 g = 0.0625 moles CH40.0625 moles CH4 ==> 0.0625 moles CO20.0625 moles CO2 x 44 g CO2/mole = 2.75 g CO2Thus, the answer would be that 1 grams of CH4 will produce 2.75 grams of CO2 after complete combustion.
Divide 96 by molecular mass.So the answer is 6mol
When 85.0 g of CH4 are mixed with 160. g of O2 the limiting reactant is __________. CH4 + 2O2 → CO2 + 2H2O
Methane (CH4) contains 1 carbon atom. The molecular mass of methane is approximately 16 g/mol.
200 g CH4 x 1 mole CH4/16 g = 12.5 moles CH4
CH4 has a molecular weight of 16, which makes the math easy. Each mole of carbon has a weight of 12. Each carbon binds with 2 oxygen to make CO2. The oxygen weighs 16. CO2 weighs 12+2*16=44 grams. Each mole of hydrogen weighs 1 g. 2 Hydrogens bind with 1 oxygen to make H2O, which has a weight of 18g. There are 4 hydrogen atoms available so we make 2 water molecules with a total weight of 36g. The total mass of products of combustion for 16 g of methane is about 80 g.
The balanced chemical equation for the combustion of methane is CH4 + 2O2 -> CO2 + 2H2O. This means that for every mole of CH4 that reacts, one mole of CO2 is produced. The molar mass of CO2 is about 44g/mol, so 22g CO2 is equivalent to 0.5 moles. Therefore, 0.5 moles of CH4 are required to produce 22g of CO2.
Divide 96 by molecular mass.So the answer is 6mol
To convert moles of CH4 (methane) to grams, you would use the molar mass of CH4, which is approximately 16.04 g/mol. Multiply the number of moles of CH4 by this molar mass to obtain the mass in grams. The formula is: grams of CH4 = moles of CH4 × 16.04 g/mol.
49.1740 g (6.02 x 1023 atoms) / (91.22 g) = 3.25 x 1023 atoms