2.6 * 6.022 * 10^23 atoms
Explanation- 1 mol of anything has 6.022 * 10^23 units. So 2.6 mol has 2.6 times this number. Also Cu is monoatomic
Note: * means multiplied; ^ means raised to the power
3.14 g Cu = # atomsTake the known mass of copper multiply it by Avogadro number and divided by the atomic weight.Atomic weight of copper:63.5 g3.14 g Cu (6.02 × 1023 atoms) / (63.5 grams) = 2.98 × 1022 atoms of Copper
1.2 g Cu * (1 mole Cu / 63.54 g Cu)*(6.022x1023 atoms Cu / mole Cu)1.137x1022 atoms of copper
The molar mass of copper is approximately 63.5 g. To find how many of these are in our sample we must divide.0.0159/63.5 = 2.5 x 10 ^ -4 = 0.00025 moles. Each mole contains the Avogadro number of atoms, i.e. 6.023 x 10 ^ 23, so in total we have 0.00025x 6.023 x 10 ^ 23 = 1.51 x 10 ^ 20 atoms approximately.
Cu(NO3)2 has 9 atoms 1 Cu atom 2 N atoms 6 O atoms
47.6 grams
1 mol Cu Atoms (6.02x10^23 atoms)
The molar mass of copper is its atomic weight on the periodic table in g/mol, and is 63.5g/mol We know that one mole of copper contains 6.022×10^23 atoms of copper . First convert given mass to moles, and moles to atoms. = 61.0 g Cu × (1 mol Cu / 63.5 g per mol) ×6.022 × 10 ^23 atom cu / 1 mol Cu) = 5.78× 10^23. atoms. 61 g Cu 5.7 ×10^23 atoms of Cu.
I assume you mean 4.6 X 10^25 atoms. This is the conversion. 4.6 X 10^25 atoms Cu ( 1mol Cu/ 6.022 X 10^23 )( 63.55 grams Cu/ 1 mol Cu ) = 4854.37 grams Cu
The mole in chemistry is also called the chemist's dozen and is defined as the amount of material containing 6.0221421 X10^23 particles(This number is called Avogadro's number) The value of mole is the number of particles in excactly 12 grams of c-12, so, if you have 12grams of c-12 , you will have 6.022x10^23 carbon atoms ,which is also a mol of C. For any other element a mol of that element is the Atomic Mass expressed as grams. 0.0265 g C find mol of C plan gC -> mol C 1 mol / 12.01 g C ( relationship; 1 mol C = 12.01 g C ) 0.0265 g C x 1 mol C / 12.01 g C = 2.21 x 10 ^-3 mol C to find atoms change to mol then times 6.022X10^23 3.10g Cu find Cu atoms plan g -> mol cu -> atoms Cu (3.10 g cu )x (1 mol Cu /63.55 g Cu ) ( 6.022 x 10^23 / 1 mol cu = 2.94 x 10^22 Cu atoms
3.14 g Cu = # atomsTake the known mass of copper multiply it by Avogadro number and divided by the atomic weight.Atomic weight of copper:63.5 g3.14 g Cu (6.02 × 1023 atoms) / (63.5 grams) = 2.98 × 1022 atoms of Copper
The density of copper (Cu) is about 8.92 g/cm3. So 1 cm3 of copper is about 8.92 g. Next find the number of moles in 8.92 g of copper by dividing by its molecular weight:8.92 g Cu / 63.54 g/mol Cu = 0.14038 mol CuBy definition 1 mol of any substance is Avogadro's number of atoms or, 6.022 x 10 23 atoms.So, 0.14038 mol Cu * [6.022x1023 atoms Cu / mol Cu] = 8.45x1022 atoms of Cu
One mole of something is 6.02 x 1023 (602,000,000,000,000,000,000,000) molicules (or atoms, if appropriate) of that substance. A gram molecular weight of anything will have one mole of molecules in it. Find out what substance you need a mole of, then find it's gram molecular weight. Take that much of the material (the gram molecular weight) and you've got your mole of that stuff.
1.2 g Cu * (1 mole Cu / 63.54 g Cu)*(6.022x1023 atoms Cu / mole Cu)1.137x1022 atoms of copper
The molar mass of copper is approximately 63.5 g. To find how many of these are in our sample we must divide.0.0159/63.5 = 2.5 x 10 ^ -4 = 0.00025 moles. Each mole contains the Avogadro number of atoms, i.e. 6.023 x 10 ^ 23, so in total we have 0.00025x 6.023 x 10 ^ 23 = 1.51 x 10 ^ 20 atoms approximately.
Cu(NO3)2 has 9 atoms 1 Cu atom 2 N atoms 6 O atoms
139 g Cu
26 cu ft equals 44,928 cubic inches.