Ok, if you have Sapling h.w....the answer is...
ions with 6d electrons..Fe2+, Ru2+, Os2+
ions with 10d electrons..Zn2+, Cd2+
the question is just asking...which element has d^6 and d^10 in its electronic configuration?
Actinium's atomic number is 89. Thus, it has 89 protons and, to keep it neutral, 89 electrons. Filling in the first 89 electron orbitals gives us an electron configuration of 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p6 6s2 5d10 6p6 4f14 7s2 6d1. When you shorten that to [Rn] 6d1 7s2, it becomes clear that actinium has 3 valence electrons, 1 in the 6d shell and 2 in the 7s shell.
For the ground state electron configuration of an element, we look at the filling of orbitals up to that element's atomic number. Tantalum (Ta) has an atomic number of 73, belonging to the transition metals, and has a ground state electron configuration of [Xe] 4f14 5d10 6s2 6p6 6d3 7s2. Counting the number of electrons in the partially filled orbitals (5d and 6d), there are 3 unpaired electrons.
Answer:According to the octet rule, there can be a max of 8 electrons in one energy level, including the valenceAnswer:The maximum number of electrons per orbitals = 2p = 6d = 10f = 14The number of valence electrons can be determined by looking at the periodic table.
The number of valence electrons in neptunium, which has an atomic number of 93, can be determined by looking at its electron configuration. Neptunium has a configuration of [Rn] 5f^4 6d^1 7s^2, so it has 3 valence electrons.
The electron configuration of hassium is: [Rn]5f14.6d6.7s2.
The number of electrons in the shells around a radon nucleus are: 2, 8, 18, 32, 18 and 8.
7wk 6d
If -6d = 42 then 6d = -42. then divide by 6, d = -7
you need 2
-6d = -42-6(7) = -42d = 7
72-6d=6 subtract 72 from both sides -6d=66 divide by -6 d=-11
yes you can
9d-19=6d+2 ... add 19 to both sides and subtract 6d from both sides... 9d-6d=2+19 3d=21 d=21/3 d=7
The pressure test for API 598 is slightly less pressure and less duration than API 6D. API 6D is specifically for pipeline valves.
6d = c Divide both sides by 6: d = c/d
API 6D exceeds API 598 in both pressure and duration.
3c - 4d = 6d + 4c Subtract 4c from both sides: -c - 4d = 6d Add 4d to both sides: -c = 10d or c = - 10d