It depends on what it is reacting with.
The molar mass of calcium carbonate is 100.1 g/mol, and the molar mass of calcium oxide is 56.08 g/mol. Therefore, 12.25 grams of calcium carbonate would produce 6.86 grams of calcium oxide after decomposition.
Calcium carbonate contains three elements: calcium, carbon, and oxygen.
A mole of calcium has 6.022 X 1023 calcium ions.
Well antimony carbonate if it exists would contain Sb3+ ions and CO32- ions-- to balance the charge the formula owuld be Sb2(CO3)3
120
There are 6 ions of carbonate present in 40 grams of calcium carbonate. This is because each molecule of calcium carbonate (CaCO3) contains one carbonate ion (CO3^2-) alongside one calcium ion (Ca^2+), giving a total of 2 ions per one molecule of calcium carbonate.
In calcium carbonate, the molar mass is 100.1 g/mol. The molar mass of calcium is 40.08 g/mol. Therefore, the percentage of calcium in calcium carbonate is 40.08/100.1 * 100 = 40%. Thus, in 40 grams of calcium carbonate, there are 40% of calcium, which is equivalent to 40/40.08 = 0.997 moles of calcium. Since calcium forms 1+ ions, there are 0.997 * 6.022 * 10^23 = 6.02 * 10^23 ions of calcium present.
There are approximately (1.20 \times 10^{24}) calcium carbonate ions in 50g of CaCO3.
2,8 moles of calcium carbonate have 240,208 g.
The molar mass of calcium carbonate is 100.1 g/mol, and the molar mass of calcium oxide is 56.08 g/mol. Therefore, 12.25 grams of calcium carbonate would produce 6.86 grams of calcium oxide after decomposition.
There are 40.08 grams of calcium in 100 grams of CaCO3. To find the amount of calcium in 418 grams of CaCO3, you can set up a proportion and calculate that there are approximately 167.2 grams of calcium in 418 grams of CaCO3.
For a partly ionically bonded compound such as calcium carbonate, the gram formula mass is substituted for a mole, which technically exists only for purely covalently bonded compounds. The gram formula mass for calcium carbonate is 100.09. Therefore, 200 grams constitutes 200/100.09 or 2.00 gram formula masses of calcium carbonate, to the justified number of significant digits.
To answer this we must first find the molar mass of calcium carbonate. CaCO3Ca= 40.08gC=12.01gO= 16.00g (we have three oxygens so 16.00x3 is 48.00g)40.08+12.01+48.00= 100.09 gNow that we have the molar mass we can find how many grams there are:1.25 moles CaCo3 x (100.09 g CaCO3/ 1 mole CaCO3)= 125.11 grams CaCO3Therefore we'd have about 125 grams of CaCO3
Calcium carbonate, CaCO3 has formula mass of 40.1+12.0+3(16.0) = 100.1Amount of CaCO3 = 1.719/100.1 = 0.0172molThere are 0.0172 moles of calcium carbonate in a 1.719 gram pure sample.
A typical stick of chalk weighs about 3.5 grams, and calcium carbonate makes up approximately 40-60% of chalk's composition. Therefore, there would be around 1.4 - 2.1 grams of calcium in a stick of chalk.
Many antacids and calcium supplements contain calcium carbonate.
Calcium carbonate contains three elements: calcium, carbon, and oxygen.