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Well antimony carbonate if it exists would contain Sb3+ ions and CO32- ions-- to balance the charge the formula owuld be Sb2(CO3)3

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How many magnesium and carbonate ions are in a unit of magnesium carbonate?

The chemical formula of magnesium carbonate is Mg(CO3)2; this molecule contain one ion of magnesium and two ions of carbonate.


How many carbonate ions are in the formula for plumbic carbonate?

The formula for plumbic carbonate is PbCO3. So there is one carbonate ion (CO3)-2 in the unit formula for PbCO3. A more modern name for this compound is lead (II) carbonate.


How many moles of ammonium ions are in 8.903 g of ammonium carbonate?

The most common form of solid ammonium carbonate is a hydrate with formula (NH4)2CO3.H2O and a gram formula unit mass of 114.10. The formula shows that each formula unit contains 2 ammonium ions. The number of formula units of ammonium carbonate is 8.903/114.10 or 0.078028. The number of formula units of ammonium ions is twice this, or 0.1561, to the justified number of significant digits.


How many magnesium and carbonate ions in a formula unit of magnesium carbonate?

Here exist: 1 ion Mg+ and ion (CO3)-.


How many oxygen atoms are in the formula Al2(CO3)3?

There are 9 oxygen atoms in the formula Al2(CO3)3. Each carbonate ion (CO3) contains 3 oxygen atoms, and there are 3 carbonate ions present in the formula.


How many moles of ammonium ions are in 8.738 g of ammonium carbonate?

To determine the number of moles of ammonium ions in 8.738 g of ammonium carbonate, first calculate the molar mass of ammonium carbonate (NH4)2CO3. Then, divide the given mass by the molar mass to find the number of moles. Since there are two ammonium ions in one formula unit of ammonium carbonate, multiply the number of moles by 2 to get the moles of ammonium ions.


How many calcium carbonate ions are present in 50g of caco3?

There are approximately (1.20 \times 10^{24}) calcium carbonate ions in 50g of CaCO3.


How many ions are in potassium ferricyanide?

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How many moles of ions are there in 0.500g of carbonate ions?

To determine the number of moles of carbonate ions in 0.500g, you first need to calculate the molar mass of carbonate (CO3^-2). The molar mass of carbonate is 60.01 g/mol. Divide the given mass (0.500g) by the molar mass to find the number of moles. This will give you approximately 0.0083 moles of carbonate ions in 0.500g.


How many sodium ions are needed to make a carbonate ion electrically neutral?

A carbonate ion (CO3^2-) has a charge of -2. Since sodium ions (Na+) have a charge of +1, two sodium ions are needed to make a carbonate ion electrically neutral.


How many elements are found in carbonate?

The formula for carbonate is CO3. This means there are 2 elements in carbonate; oxygen and carbon.


How many moles of ammonium ions are in 6.965 of ammonium carbonate?

To find the number of moles of ammonium ions, we first calculate the molar mass of ammonium carbonate (NH4)2CO3. It is 96.086 g/mol. Then we can find the moles of (NH4)2 cations in 6.965 g by dividing the mass by the molar mass. This gives us 0.0726 moles of ammonium ions.