Wiki User
∙ 11y agoYou need 36,03 g glucose.
Wiki User
∙ 7y agoTo make a 2 M solution of glucose in 100mL, you would need to calculate the molecular weight of glucose (180.16 g/mol) and then use the formula:
mass (g) = molarity (M) x volume (L) x molecular weight (g/mol)
mass = 2 mol/L x 0.1 L x 180.16 g/mol = 36.032 grams of glucose.
Wiki User
∙ 13y ago0,144 g
Wiki User
∙ 12y ago8 grams :)
To make a 100ml 1M solution of Sodium Chloride, you would dissolve 5.85 grams of NaCl in enough water to make 100ml of solution. This molarity calculation is based on the molar mass of NaCl (58.44 g/mol).
To prepare a 2% solution of ferric chloride in 100ml of water, you would need to add 2 grams of ferric chloride. This is calculated by multiplying the volume of the solution (100ml) by the desired concentration (2%) and converting it to grams.
400 mls would require 40g of glucose for a 10% solution and thus 20g for a 5% solution.
To prepare a 100% solution of glucose in water, you would need anhydrous glucose powder. Since a 100% solution means pure glucose dissolved in water, you would mix the desired amount of glucose into water until fully dissolved. It's important to note that a 100% glucose solution is highly concentrated and may not be appropriate for certain applications.
To prepare a 10% glucose solution, you would mix 10 grams of glucose with enough water to make a total solution volume of 100 ml. This means the final solution would contain 10 grams of glucose and 90 ml of water.
To prepare a 50mm glucose solution, you would need to dissolve 9g of glucose in enough water to make 100mL of solution. This would give you a solution with a concentration of 50mm (millimolar).
To make a 100ml 1M solution of Sodium Chloride, you would dissolve 5.85 grams of NaCl in enough water to make 100ml of solution. This molarity calculation is based on the molar mass of NaCl (58.44 g/mol).
It would be 12.6g of IKI to obtain the 100mL solution of 0.300 M IKI.
It would be 12.6g of IKI to obtain the 100mL solution of 0.300 M IKI.
To prepare a 2% solution of ferric chloride in 100ml of water, you would need to add 2 grams of ferric chloride. This is calculated by multiplying the volume of the solution (100ml) by the desired concentration (2%) and converting it to grams.
400 mls would require 40g of glucose for a 10% solution and thus 20g for a 5% solution.
To prepare a 100% solution of glucose in water, you would need anhydrous glucose powder. Since a 100% solution means pure glucose dissolved in water, you would mix the desired amount of glucose into water until fully dissolved. It's important to note that a 100% glucose solution is highly concentrated and may not be appropriate for certain applications.
The Molecular Weight of NaCl = 58.5 So to make 1L of 4M NaCl solution you need 4*58.5=234g of NaCl So to make 100mL of the above solution you need 23.4 grams of NaCl
To prepare a 10% glucose solution, you would mix 10 grams of glucose with enough water to make a total solution volume of 100 ml. This means the final solution would contain 10 grams of glucose and 90 ml of water.
percent concentration = (mass of solute/volume of solution) X 100 To solve for mass of solute, mass of solute = (percent concentration X volume of solution)/100 So, mass of solute = (10% X 100mL)/100 = 10g
To make a 1 molar solution of glucose in 0.5 L of water, you would need to dissolve 90.1 grams of glucose powder. This is because the molar mass of glucose (C6H12O6) is approximately 180.2 g/mol, and for a 1 molar solution in 0.5 L of water, you would need 1 mole of glucose, which is 180.2 grams.
To prepare a 6M NaCl solution, you would need to dissolve 58.44 grams of NaCl in water to make a 1 liter solution. To prepare a different volume, you would adjust the amount of NaCl accordingly using the molarity equation: Molarity = moles of solute / volume of solution in liters.