Balanced equation.
2H2 + O2 --> 2H2O
5 moles H2 (2 moles H2O/2 mole H2)(18.016 grams/1 mole H2O)
= 90 grams of water
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PosV = nrt.....solve for n pv / rt = n 0.0027atm x 0.15L / (0.0821L-atm/mole-K x 298K) = 1.657x10^-5moles 0.231g / 1.657x10^-4moles = 13940.98g/mole
to solve this you must have the molecular weight of NaoH and you can get this by add the molar masses together (H=1 , O=16 , Na-23 ) then multiply the no of moles by the molecular mass that is for mole gram conversion so you have (23+16+1)= 40 and already you have multiplied (2.40)=80 then 2 . 40 = 120 then 80 / 40 = 2 the answer is 2
I'm assuming that your instructor is using the terms mass and weight interchangeably. First determine the molar mass of each compound by multiplying the molar mass of each element by its subscript and add them together. The molar mass of an element is its atomic weight on the periodic table in grams. Molar mass of sodium nitrate (NaNO3) (1 atom Na x 22.98970g/mol Na) + (1 atom N x 14.0067g/mol N) + (3 atoms O x 15.9994g/mol O) = 84.9946g/mol NaNO3 Molar mass of carbon dioxide (CO2) (1 atom C x 12.0107g/mol C) + (2 atoms O x 15.9994g/mol O) = 44.0095g/mol CO2 Now multiply the molar mass for each compound by the number given and compare the results to determine which has the greater mass. 5mol NaNO3 x 84.9946g/mol NaNO3 = 424.973g NaNO3 4 mol CO2 x 44.0095g/mol CO2 = 176.038 So 5 moles of sodium nitrate has a mass greater than 4 moles of carbon dioxide.