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to solve this you must have the molecular weight of NaoH and you can get this by add the molar masses together (H=1 , O=16 , Na-23 )
then multiply the no of moles by the molecular mass that is for mole gram conversion
so you have (23+16+1)= 40
and already you have multiplied (2.40)=80
then 2 . 40 = 120
then 80 / 40 = 2
the answer is 2
What else can I help you with?
How many grams of NaOH(MW40.0) are there in 400.0 ml of a 0.175 M NaOH solution?
To calculate the grams of NaOH in the solution, you first need to find the moles of NaOH present in 400.0 ml of the solution. The moles of NaOH can be calculated using the formula: moles = molarity x volume (in liters). Once you have the moles of NaOH, you can then calculate the grams using the formula: grams = moles x molecular weight.
How many grams of NaOH are in 350 mL of a 2.5 M of NaOH solution?
To calculate the grams of NaOH in the solution, first determine the moles of NaOH using the molarity and volume. Then, convert moles to grams using the molar mass of NaOH. The molar mass of NaOH is 40 g/mol.
If you have 60 grams of sodium hydroxide NaOH (FW 40 gramsmole) how many moles of sodium hydroxide would you have?
60 g NaOH x 1 mole NaOH/40 g NaOH = 1.5 moles NaOH
How many grams of NaOH are needed to prepare 250mL of 205 M of NaOH?
To calculate the grams of NaOH needed, you first need to find the moles of NaOH required: 205 M concentration means 205 moles/L. So, for 250 mL (0.25 L), you multiply 0.25 L by 205 moles/L to get 51.25 moles. Finally, using the molar mass of NaOH (40 g/mol), you can convert moles to grams by multiplying 51.25 moles by 40 g/mol to find you need 2050 grams of NaOH.
How many grams of NaOH are contained in 500mL of 0.5M NaOH?
First, you must find the amount of moles of NaOH, using the concentration and volume given. By lowercase m, I'm assuming you mean molality, or molals of solution, which is the equation:molality (m) = (moles of solute) / (total volume of solution (in liters))To solve for moles of NaOH, your solute, rearrange the equation by multiplying volume on both sides to get:moles solute = (molality)(total volume of solution)Next, just plug in the information you know, which is 500 mL for the total volume and 125 m for the molality.***Volume for concentration problems must be converted to liters, so remember that 1 L = 1000 mLmoles NaOH = (125 m)(0.500 L) = 62.5 molesFinally, convert this to grams by finding the molar mass of NaOH using the periodic table:22.99 + 16.00 + 1.008 = 39.998 g/mol62.5 moles (39.998 g) / (1 mol) =249.875 grams NaOH
How many grams of NaOH are there in 5.2 moles NaOH?
208g NaOH
How many grams of NaOH(MW40.0) are there in 400.0 ml of a 0.175 M NaOH solution?
To calculate the grams of NaOH in the solution, you first need to find the moles of NaOH present in 400.0 ml of the solution. The moles of NaOH can be calculated using the formula: moles = molarity x volume (in liters). Once you have the moles of NaOH, you can then calculate the grams using the formula: grams = moles x molecular weight.
How many moles are in gram of NaOH?
moles = mass/Mr moles = 100/(23+16+1) moles of NaOH = 2.5mol
How many grams of NaOH are in 350 mL of a 2.5 M of NaOH solution?
To calculate the grams of NaOH in the solution, first determine the moles of NaOH using the molarity and volume. Then, convert moles to grams using the molar mass of NaOH. The molar mass of NaOH is 40 g/mol.
If you have 60 grams of sodium hydroxide NaOH (FW 40 gramsmole) how many moles of sodium hydroxide would you have?
60 g NaOH x 1 mole NaOH/40 g NaOH = 1.5 moles NaOH
How many grams of NaOH are needed to prepare 250mL of 205 M of NaOH?
To calculate the grams of NaOH needed, you first need to find the moles of NaOH required: 205 M concentration means 205 moles/L. So, for 250 mL (0.25 L), you multiply 0.25 L by 205 moles/L to get 51.25 moles. Finally, using the molar mass of NaOH (40 g/mol), you can convert moles to grams by multiplying 51.25 moles by 40 g/mol to find you need 2050 grams of NaOH.
How many grams of NaOH are contained in 500mL of 0.5M NaOH?
First, you must find the amount of moles of NaOH, using the concentration and volume given. By lowercase m, I'm assuming you mean molality, or molals of solution, which is the equation:molality (m) = (moles of solute) / (total volume of solution (in liters))To solve for moles of NaOH, your solute, rearrange the equation by multiplying volume on both sides to get:moles solute = (molality)(total volume of solution)Next, just plug in the information you know, which is 500 mL for the total volume and 125 m for the molality.***Volume for concentration problems must be converted to liters, so remember that 1 L = 1000 mLmoles NaOH = (125 m)(0.500 L) = 62.5 molesFinally, convert this to grams by finding the molar mass of NaOH using the periodic table:22.99 + 16.00 + 1.008 = 39.998 g/mol62.5 moles (39.998 g) / (1 mol) =249.875 grams NaOH
How many grams does 2.2 moles of NaOH weigh?
2.2 moles of NaOH weigh 99.55 grams. This is calculated by multiplying the number of moles by the molar mass of NaOH, which is 40 grams per mole for Na (22.99 g/mol) + O (16.00 g/mol) + H (1.01 g/mol).
How many grams of NaOH are in 350 mL of a 5.7 M NaOH solution?
Molarity = moles of solute/Liters of solution. ( 350 ml = 0.350 Liters ) 5.7 M NaOH = moles NaOH/0.350 Liters = 1.995 moles NaOH (39.998 grams/1 mole NaOH) = 78 grams NaOH needed ------------------------------------
How many grams of solute in 1.8 L of a 3.5 M NaOH solution?
To calculate the grams of solute, you need to first find the molar mass of NaOH (40 g/mol). Then, use the formula grams = moles x molar mass. The moles of NaOH in 1.8 L of a 3.5 M solution is 6.3 moles. Therefore, the grams of NaOH in 1.8 L of a 3.5 M solution is 252 grams.
How many grams of NaOH are formed from reacting 120g sodium carbonate with excess calcium hydroxide?
Write out the equation, and remember to balance each side.Na2CO3 + Ca(OH)2 --> 2NaOH + CaCO3Molecular WeightsNa2CO3: 106 grams/moleNaOH: 40 grams/moleAlways convert your reagents into moles.(120g Na2CO3) x (1 mole Na2CO3/106 grams Na2CO3) = 1.132 molesAccording to the balanced equation, 1 molecule of Na2CO3 generates 2 molecules of NaOH.(1.132 moles Na2CO3) x (2 moles NaOH/1 mole Na2CO3) = 2.264 moles NaOHNow determine the number of grams from 2.264 moles of NaOH.(2.264 moles NaOH) x (40 grams/ 1 mole NaOH) = 90.57 grams NaOH formed.To prevent rounding off too many times, carry out the dimensional analysis in one step:(120g Na2CO3) x (1 mole Na2CO3/106 grams Na2CO3) x(2 moles NaOH/1 mole Na2CO3) x (40 grams/ 1 mole NaOH) = 90.57 grams NaOH
How many grams of of NaOH are required to prepare 200 mL of a 0.450 M solution?
Approximately 4.50 grams of NaOH are required to prepare 200 mL of a 0.450 M solution. This can be calculated using the formula: moles = Molarity x Volume (in L), and then converting moles to grams using the molar mass of NaOH.
