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How many fluoride ions are in 1.46 moles of aluminum fluoride?
There would be 4.38 moles of fluoride ions in 1.46 moles of aluminum fluoride, as the formula for aluminum fluoride is AlF3 with three fluoride ions per molecule of aluminum fluoride.
How many ions are in sulfate in Al2SO4?
There are 3 ions in the formula Al2SO4 (2 aluminum and 1 sulfate), but this formula is wrong. The formula of aluminum sulfate is Al2(SO4)3 which contains 5 ions: 2 aluminum ions and 3 sulfate ions.
What is the ratio of aluminum ions to sulfur ions in the formula Al2S3?
The ratio of aluminum ions to sulfur ions in the formula Al2S3 is 2:3. This means that for every 2 aluminum ions, there are 3 sulfur ions present in the compound.
How many chlorine ions are required to bond with one aluminuim ion?
Three chlorine ions are required to bond with one aluminum ion in order to form the compound aluminum chloride. This results in a stable compound with a 1:3 ratio of aluminum to chlorine ions.
How many chlorine ions are required to bond with aluminum ion?
Three chlorine ions are required to bond with one aluminum ion to form the compound aluminum chloride. This is because aluminum has a 3+ charge and chlorine has a 1- charge, so the formula for aluminum chloride is AlCl3.
How many fluoride ions are in 1.46 moles of aluminum fluoride?
There would be 4.38 moles of fluoride ions in 1.46 moles of aluminum fluoride, as the formula for aluminum fluoride is AlF3 with three fluoride ions per molecule of aluminum fluoride.
How many chloride ions are required to neutralize one aluminum ion?
Aluminum is 3+ and chloride is 1-. So, you need 3 chloride ions to neutralize 1 aluminum ion.
How many ions are in sulfate in Al2SO4?
There are 3 ions in the formula Al2SO4 (2 aluminum and 1 sulfate), but this formula is wrong. The formula of aluminum sulfate is Al2(SO4)3 which contains 5 ions: 2 aluminum ions and 3 sulfate ions.
What is the ratio of aluminum ions to sulfur ions in the formula Al2S3?
The ratio of aluminum ions to sulfur ions in the formula Al2S3 is 2:3. This means that for every 2 aluminum ions, there are 3 sulfur ions present in the compound.
How many ions of bromide will combine with one of aluminum?
Three ions of bromide will combine with one ion of aluminum to form aluminum bromide (AlBr3). This is because aluminum has a +3 charge and bromide ions each have a -1 charge, so three bromide ions are needed to balance the +3 charge of aluminum.
How many chlorine ions are required to bond with one aluminuim ion?
Three chlorine ions are required to bond with one aluminum ion in order to form the compound aluminum chloride. This results in a stable compound with a 1:3 ratio of aluminum to chlorine ions.
Which of these metals will be oxidized by the ions of aluminum?
Metals with a lower reduction potential than aluminum will be oxidized by aluminum ions. For example, magnesium and zinc are metals that can be oxidized by aluminum ions.
How many chlorine ions are required to bond with aluminum ion?
Three chlorine ions are required to bond with one aluminum ion to form the compound aluminum chloride. This is because aluminum has a 3+ charge and chlorine has a 1- charge, so the formula for aluminum chloride is AlCl3.
What ions are in the formula aluminum chloride?
The formula for aluminum chloride is AlCl3, which consists of aluminum ions (Al3+) and chloride ions (Cl-). In the compound, aluminum donates three electrons to chloride, resulting in the formation of three chloride ions for every aluminum ion.
What is the formula for the compound formed between aluminum ions oad phosphate ions is?
The compound formed between aluminum ions (Al^3+) and phosphate ions (PO4^3-) is aluminum phosphate, with the formula AlPO4.
HOW many chloride ions are required to bond with one aluminum ion?
Three chloride ions are required to bond with one aluminum ion because aluminum has a +3 charge and chloride has a -1 charge. This results in the formula AlCl3.
How many chloride ions are there in 3 mol of aluminum chloride?
Aluminum chloride contains 3 chlorine atoms per molecular unit. Therefore, in 3 moles there are 3 times Avogadro's number of chloride ions = 1.807 X 1024.
