So, you're given 75.0 grams of C2H2Cl4 and you want to find how many L of Cl2.
Reaction: 2Cl2 + C2H2 --> C2H2Cl4
Understand the information you need to fill your conversion factor.
You'll want to know:
how many grams are in 1 mol C2H2Cl4 (167.84 g)[added atomic weight from Periodic Table]
mole to mole ratio of Cl2 and C2H2Cl4 (2:1)[given in reaction]
how many liters are in a mole (22.4 L/mol)[universal]
Then, you want to set up your conversion factor.
75.0 g C2H2Cl4 x ( 1 mol C2H2Cl4/ 167.84 g C2H2Cl4 ) x (2 mol Cl2/1 mol C2H2Cl4) x (22.4 L/ 1 mol) = ?
To calculate the grams of NaOH needed, use the formula: grams = molarity x volume x molar mass. First, convert the volume to liters (4 liters). Next, calculate the grams using 8 M as the molarity and the molar mass of NaOH. This will give you the amount of NaOH required to make 4 liters of 8 M NaOH solution.
To calculate the grams of sodium thiosulfate needed, first determine the molar mass of Na2S2O3 (158 g/mol). Step 1: Calculate the number of moles needed using the formula: moles = Molarity * Volume (in liters) moles = 0.025 * 2 (since 2000 ml is 2 liters) = 0.05 moles Step 2: Calculate the grams needed using the formula: grams = moles * molar mass grams = 0.05 * 158 = 7.9 grams Therefore, you would need 7.9 grams of sodium thiosulfate to make 2000 ml of a 0.025N solution.
The question was asked in a roundabout way, but I think you mean that if a saturated solution of sodium chloride (salt) and water contained 2 grams of sodium chloride and 5 liters of water, than how many grams of salt would be needed to make a saturated solution with 28 liters of water. First off, the one unit you gave me was mass, and the other was volume, so technically I couldn't discover how many grams of salt would be needed. However, if I can safely assume that the water in the first and second example were under the same conditions, than the answer would be 11.2 grams. Next time you submit a question be sure you are clear about what you're asking, otherwise you may receive an answer that doesn't adequately address the question you meant to ask.
To make a 2 molar solution of hydrochloric acid, you would need to know the volume of the solution you want to make. Once you have the volume, you can use the molarity formula (M = moles of solute / liters of solution) to calculate the grams of hydrochloric acid needed.
Molarity = moles of solute/Liters of solution ( 220.0 ml = 0.220 Liters ) 0.500 M KOH = moles KOH/0.220 Liters = 0.110 moles KOH (56.108 grams/1 mole KOH) = 6.17 grams solid KOH needed
To calculate the grams of NaOH needed, use the formula: grams = molarity x volume x molar mass. First, convert the volume to liters (4 liters). Next, calculate the grams using 8 M as the molarity and the molar mass of NaOH. This will give you the amount of NaOH required to make 4 liters of 8 M NaOH solution.
To calculate the grams of sodium thiosulfate needed, first determine the molar mass of Na2S2O3 (158 g/mol). Step 1: Calculate the number of moles needed using the formula: moles = Molarity * Volume (in liters) moles = 0.025 * 2 (since 2000 ml is 2 liters) = 0.05 moles Step 2: Calculate the grams needed using the formula: grams = moles * molar mass grams = 0.05 * 158 = 7.9 grams Therefore, you would need 7.9 grams of sodium thiosulfate to make 2000 ml of a 0.025N solution.
The question was asked in a roundabout way, but I think you mean that if a saturated solution of sodium chloride (salt) and water contained 2 grams of sodium chloride and 5 liters of water, than how many grams of salt would be needed to make a saturated solution with 28 liters of water. First off, the one unit you gave me was mass, and the other was volume, so technically I couldn't discover how many grams of salt would be needed. However, if I can safely assume that the water in the first and second example were under the same conditions, than the answer would be 11.2 grams. Next time you submit a question be sure you are clear about what you're asking, otherwise you may receive an answer that doesn't adequately address the question you meant to ask.
To make a 2 molar solution of hydrochloric acid, you would need to know the volume of the solution you want to make. Once you have the volume, you can use the molarity formula (M = moles of solute / liters of solution) to calculate the grams of hydrochloric acid needed.
You cannot convert grams to liters. 500g = 17.636981 ounces.
Molarity = moles of solute/Liters of solution ( 220.0 ml = 0.220 Liters ) 0.500 M KOH = moles KOH/0.220 Liters = 0.110 moles KOH (56.108 grams/1 mole KOH) = 6.17 grams solid KOH needed
Molarity = moles of solute/Liters of solution ( 918 ml = 0.918 liters )rearranged algebraically,moles of solute = Liters of solution * Molaritymoles of NaOH = (0.918 l)(0.4922 M)= 0.45184 moles NaOH=======================so,0.45184 moles NaOH (39.998 grams/1 mole NaOH)= 18.1 grams sodium hydroxide needed============================
The conversion from grams to liters depends on the density of the substance. If you know the density of the substance, you can use the formula: volume (liters) = mass (grams) / density (g/ml) to find the volume in liters. If the substance is water, 300 grams would be roughly 0.3 liters.
To find the grams of sodium fluoride needed, use the formula: grams = moles x molar mass. First calculate the moles by multiplying the volume (6.3 L) by the molarity (3.6 mol/L). Then multiply the moles by the molar mass of sodium fluoride (41.99 g/mol) to find the grams required. In this case, approximately 920 grams of sodium fluoride are needed.
A US pint is 473 grams. - An Imperial pint is 568 grams
89.3
To find the amount of ammonium carbonate needed, use the formula: grams = moles * molar mass. First, calculate moles using the given volume and molarity: moles = volume (L) * molarity (mol/L). Then, multiply the moles by the molar mass of ammonium carbonate (96.09 g/mol) to find the grams needed.