1.34
33 grams aluminum (1 mole Al/26.98 grams) = 1.2 moles of aluminum ================
2
16.2 grams aluminum (1 mole Al/26.98 grams)(6.022 X 1023/1 mole Al) = 3.62 X 1023 atoms of aluminum ------------------------------------------
The answer is 1 527 mg aluminium.
671
17.9 grams
1,99 grams of aluminum is equal to 0,0737 moles.
33 grams aluminum (1 mole Al/26.98 grams) = 1.2 moles of aluminum ================
2
10 grams aluminum (1 mole Al/26.98 grams) = 0.37 moles of aluminum ---------------------------------
16.3106
4,12 grams aluminum sulfate is equivalent to 0,012 moles (for the anhydrous salt).
266,86 g aluminium chloride are obtained.
16. 2 grams aluminum (1 mole Al/26.98 grams)(6.022 X 1023/1 mole Al) = 3.62 X 1023 atoms of aluminum -------------------------------------------
9 grams aluminum (1 mole Al/26.98 grams) = 0.3 moles aluminum ==============
16.2 grams aluminum (1 mole Al/26.98 grams)(6.022 X 1023/1 mole Al) = 3.62 X 1023 atoms of aluminum ------------------------------------------
The answer is 1 527 mg aluminium.