One molecule of CaCO3 is composed of one calcium (Ca) atom, one carbon (C) atom, and three oxygen (O) atoms, for a total of five atoms.
Three molecules of calcium carbonate (CaCO3) has nine(9) oxygens. Think of 3CaCO3 = CaCO3 + CaCO3 + CaCO3. Each molecule of CaCO3 has ;- 1 atoms of calcium (Ca) 1 atom of carbon (C) 3 atoms of oxygen (O3 = O + O + O). So if one molecules of CaCO3 has 3 oxygens, then three molecules of CaCO3 has 3 x 3 = 9 oxygens. The answer!!!!!
In the formula 2CaCO3, there are 2 molecules of calcium carbonate (CaCO3) in total. Each molecule of calcium carbonate consists of one calcium atom, one carbon atom, and three oxygen atoms.
250 grams CaCO3 (1 mole CaCO3/100.09 grams) = 2.50 moles of calcium carbonate
Molar mass of CaCO3 = 66.1221g CaCO3/mole CaCO3. This means that 1 mole CaCO3 = 66.1221g CaCO3. To find the mass of 4.5 mole CaCO3, complete the following calculation: 4.5g CaCO3 X 1mol CaCO3/66.1221g CaCO3 = 0.068 mole CaCO3.
There are approximately (1.20 \times 10^{24}) calcium carbonate ions in 50g of CaCO3.
Three molecules of calcium carbonate (CaCO3) has nine(9) oxygens. Think of 3CaCO3 = CaCO3 + CaCO3 + CaCO3. Each molecule of CaCO3 has ;- 1 atoms of calcium (Ca) 1 atom of carbon (C) 3 atoms of oxygen (O3 = O + O + O). So if one molecules of CaCO3 has 3 oxygens, then three molecules of CaCO3 has 3 x 3 = 9 oxygens. The answer!!!!!
They are molecules.
A mole of H2 molecules contains 6.023 x 10^(23) H2 molecules or 2 moles of H atoms (since each molecules has 2 atoms). A mole of CaCO3 (calcium carbonate) has one mole (Avogadro number) of Ca atoms, one mole of C atoms and 3 moles of O atoms.
In the formula 2CaCO3, there are 2 molecules of calcium carbonate (CaCO3) in total. Each molecule of calcium carbonate consists of one calcium atom, one carbon atom, and three oxygen atoms.
2.
There are three carbon atoms in one molecule of CaCO3 (calcium carbonate).
250 grams CaCO3 (1 mole CaCO3/100.09 grams) = 2.50 moles of calcium carbonate
Molar mass of CaCO3 = 66.1221g CaCO3/mole CaCO3. This means that 1 mole CaCO3 = 66.1221g CaCO3. To find the mass of 4.5 mole CaCO3, complete the following calculation: 4.5g CaCO3 X 1mol CaCO3/66.1221g CaCO3 = 0.068 mole CaCO3.
There are 2 oxygen atoms in one molecule of CaCO3. To calculate the number of oxygen atoms in 50 grams of CaCO3, you first need to find the number of moles of CaCO3 using its molar mass. Then, multiply the number of moles by the number of atoms of oxygen per molecule of CaCO3 (2) to find the total number of oxygen atoms.
3
There are approximately (1.20 \times 10^{24}) calcium carbonate ions in 50g of CaCO3.
It is CaCO3.....it is the same as marbleFormula: CaCO3