How many moles are in 12.3 grams of H2O?

Answer 1

Are you asking for moles of Calcium, moles of Oxygen, moles of Hydrogen, or moles of calcium hydroxide? The respective answers are .161991414, .323982829, .323982829 , and .161991414 moles. For an explanation, see the following question: How_many_moles_of_calcium_are_in_15.5_g_calcium_chloride

Answer 2

Magnesium is an element and does not technically have moles. The corresponding property for elements and non-molecular compounds is called "gram formula mass, and its value for magnesium is 24.305. Therefore, 12 g of magnesium comprises 12/24.305 or 0.49 gram formula masses, to the justified number of significant digits.

Answer 3

Magnesium iodide has a molar mass of 278g/mol. Set this up in an algebraic direct proportion where 278/1=12.15/x, and solve for x to get 0.0437 moles. This is the answer. This is called a mass-mole conversion, and it's an essential step for stoichiometry and many other calculations.

Answer 4

For this you need the atomic (molecular) mass of Mg(OH)2. Take the number of grams and divide it by the Atomic Mass. Multiply by one mole for units to cancel. Mg(OH)2=58.3 grams

12.5 grams Mg(OH)2 / (58.3 grams)= .214 moles Mg(OH)2

Answer 5

Formula mass of magnesium carbonate, MgCO3 = 24.3+12.0+3(16.0) = 84.3

Amount of MgCO3 = 12.60/84.3 = 0.149mol

There are 0.149 moles of magnesium carbonate in a 12.60g pure sample.

Answer 6

There are 24.31 grams in 1 mol of Mg so you take 12.15 and divide that by 24.31 and you get 0.499794323 which Im pretty sure is how many moles are in 12.15g of Mg.

Answer 7

There are 0.684 moles in 12.3 grams of H2O. This is calculated by dividing the given mass by the molar mass of water (18 g/mol), which gives the number of moles.

Answer 8

12.3/18. Figure it out.

Answer 9

291.6 mol