Use the formulae n=m/M
Where,
n - number of mols
m - mass
M - molar mass
Molar mass of Mg = 24
n=202/24 = 8.416
13.5g Mg(NO3)2 x 1 mol Mg(NO3)2/148.3 = 0.0910 mol Mg(NO3)2
If you think to the mass of 88,1 moles of magnesium this is 2141,27 g.
280mg is 0.28 grams (divide mg by 1,000 to get grams).
I assume that is 28.0 grams.28.0 grams MgCl2 (1 mole MgCl2/95.21 grams)= 0.294 moles magnesium chloride==========================Now,One mole Mg 2+ = 0.294 moles Mg 2+ ions=============================2 moles Cl - = 0.588 moles Cl - ions=========================
524mg is 0.524g (mg divided by 1,000 = grams).
1.346 grams Mg (1 mole Mg/24.31 grams) = 0.05537 moles magnesium
13.5g Mg(NO3)2 x 1 mol Mg(NO3)2/148.3 = 0.0910 mol Mg(NO3)2
For this you need the atomic mass of Mg. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. Mg= 24.3 grams35.0 grams Mg / (24.3 grams) = 1.44 moles Mg
For this you need the atomic mass of Mg. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel.4.637 grams Mg / (24.3 grams) = .191 moles Mg
Aspirins formula is C9H8O4 300 mg Aspirin (1 gram/1000 mg)(1 mole aspirin/180.154 grams) = 0.00167 moles aspirin
8,23.1023 atoms Mg is equivalent to 1,366 moles.
Two moles KOH for one mole Mg(OH)2; so for 4 moles KOH - two moles Mg(OH)2.And two moles Mg(OH)2 is equal to 116,64 g.
Two moles KOH for one mole Mg(OH)2; so for 4 moles KOH - two moles Mg(OH)2.And two moles Mg(OH)2 is equal to 116,64 g.
There are 18.9 moles in 225.8 mg. This is a math problem.
For this you need the atomic mass of Na. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel.2.1 moles Na × (23.0 grams) = 48.3 grams Na
The answer is 0,615 moles.
If you think to the mass of 88,1 moles of magnesium this is 2141,27 g.