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How many moles in 13.5 grams of magnesium nitrate?
To find the number of moles in 13.5 grams of magnesium nitrate, you need to divide the given mass by the molar mass of magnesium nitrate. The molar mass of magnesium nitrate (Mg(NO3)2) is 148.31 g/mol. Moles of magnesium nitrate = 13.5 grams / 148.31 g/mol ≈ 0.091 moles
How many moles of sodium borohydride are used in 100 mg?
To calculate the number of moles of sodium borohydride in 100 mg, you need to know the molar mass of the compound, which is 37.83 g/mol. First, convert 100 mg to grams (0.1 g), then divide by the molar mass to get the number of moles, which is approximately 0.0026 moles.
How many grams are in 88.1 moles of magnesium?
If you think to the mass of 88,1 moles of magnesium this is 2141,27 g.
What is the mass of HCl that would be required to completely react with 5.2 grams of Mg?
The balanced chemical equation for the reaction between HCl and Mg is: Mg + 2HCl -> MgCl2 + H2. One mole of Mg reacts with 2 moles of HCl. Calculate the moles of Mg in 5.2 grams using the molar mass of Mg. Then use the mole ratio to find the moles of HCl needed, and finally calculate the mass of HCl using its molar mass.
How many grams are in 469.1 mg?
469.1mg equates to 0.4691 grams (mg divided by 1,000 = grams)** 1 gram = 1,000mg
How many moles is 1.346g of Mg?
1.346 grams Mg (1 mole Mg/24.31 grams) = 0.05537 moles magnesium
How many moles in 13.5 grams of magnesium nitrate?
To find the number of moles in 13.5 grams of magnesium nitrate, you need to divide the given mass by the molar mass of magnesium nitrate. The molar mass of magnesium nitrate (Mg(NO3)2) is 148.31 g/mol. Moles of magnesium nitrate = 13.5 grams / 148.31 g/mol ≈ 0.091 moles
How many moles are in 29.4mg of BrI?
To find the number of moles, you first need to convert 29.4 mg of BrI to grams by dividing by 1000 to get 0.0294 g. Next, calculate the number of moles by dividing the mass in grams by the molar mass of BrI (which is 207.8 g/mol). Therefore, there are approximately 0.000141 moles of BrI in 29.4 mg.
How many moles are in 13.2 grams of magnesium?
For this you need the atomic mass of Mg. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. Mg= 24.3 grams35.0 grams Mg / (24.3 grams) = 1.44 moles Mg
How do you calculate the number of moles in 4.637 grams in Mg?
For this you need the atomic mass of Mg. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel.4.637 grams Mg / (24.3 grams) = .191 moles Mg
How many moles of sodium borohydride are used in 100 mg?
To calculate the number of moles of sodium borohydride in 100 mg, you need to know the molar mass of the compound, which is 37.83 g/mol. First, convert 100 mg to grams (0.1 g), then divide by the molar mass to get the number of moles, which is approximately 0.0026 moles.
How many grams are in 88.1 moles of magnesium?
If you think to the mass of 88,1 moles of magnesium this is 2141,27 g.
How many mg in 2 g?
For this you need the atomic mass of Na. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel.2.1 moles Na × (23.0 grams) = 48.3 grams Na
How many moles of Mg contain 8.231023 atoms Mg?
8,23.1023 atoms Mg is equivalent to 1,366 moles.
How many moles are in 225.8 g of Mg?
There are 18.9 moles in 225.8 mg. This is a math problem.
Which equation shows how to calculate how many grams (g) of Mg(OH)2 would be produced from 4 mol of KOH The balanced reaction is MGCl2 plus 2KOH Mg(OH)2 plus 2KCl?
Two moles KOH for one mole Mg(OH)2; so for 4 moles KOH - two moles Mg(OH)2.And two moles Mg(OH)2 is equal to 116,64 g.
Which equation shows how to calculate how many grams(g) of Mg(OH)2 would be produced from 4 mol KOH. The balanced reaction is mgcl2 plus 2koh mg(oh)2 plus 2kcl?
Two moles KOH for one mole Mg(OH)2; so for 4 moles KOH - two moles Mg(OH)2.And two moles Mg(OH)2 is equal to 116,64 g.
