Simply divide by the number that signifies moles of any thing; Avogadro's number.
3.4 X 10^23/6.022 X 10^23
= 0.56 moles of H2SO4
Quite a few!
2.4 X 1024 molecules SO3 (1 mole SO3/6.022 X 1023)
= 4.0 moles of sulfur trioxide
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I believe it's .56 moles H2SO4
The answer is 0,565 moles.
.56 moles
Ff
.565 MOLES
9.62 Mol H2SO4 ( 6.022 X 10^23/1mol H2SO4 ) = 5.79 X 10^24 molecules of H2SO4
how many molecules are containd in 55.0g of H2SO4
Zn + H2SO4 ---> ZnSO 4 + H2 so one mole of zinc and 1 mole of sulfuric acid produces one mole of hydrogen molecules and thus two moles of hydrogen atoms. So 0.36 moles of zinc will produce 0.36 moles of hydrogen molecules and thus 0.72 moles of hydrogen atoms.
5 moles
.565 MOLES
9.62 Mol H2SO4 ( 6.022 X 10^23/1mol H2SO4 ) = 5.79 X 10^24 molecules of H2SO4
how many molecules are containd in 55.0g of H2SO4
Zn + H2SO4 ---> ZnSO 4 + H2 so one mole of zinc and 1 mole of sulfuric acid produces one mole of hydrogen molecules and thus two moles of hydrogen atoms. So 0.36 moles of zinc will produce 0.36 moles of hydrogen molecules and thus 0.72 moles of hydrogen atoms.
5 moles
196 grams H2SO4 (1 mole H2SO4/98.096 grams)(6.022 X 10^23/1 mole H2SO4) = 1.20 X 10^24 molecules of sulfuric acid
3.01 x 10 to the 23 power of molecules
Molarity = moles of solute/volume of solution 0.324 M H2SO4 = moles H2SO4/500 ml 162 millimoles, or, more precisely to the question 0.162 moles H2SO4
1.5 moles of Hydrogen. In every mole of H2SO4 (Sulfuric Acid) there are 2 moles of Hydrogen atoms. So, in .75 moles of Sulfuric Acid, there would be 1.5 (double the moles of sulfuric acid) moles of Hydrogen.
Sulfuric acid is not obtained from water.
Five molecules of H2SO4 contains 20 atoms of Oxygen
Balanced equation first. 2NaOH + H2SO4 -> Na2SO4 +2H2O Molarity = moles of solute/Liters of solution 0.259 M H2SO4 = moles H2SO4/0.359 liters = 0.09298 moles H2SO4 0.191 M NaOH = moles of NaOH/0.510 liters = 0.09741 moles NaOH ( Let us find limiting reactant ) 0.09298 moles H2SO4 (1 mole H2SO4/2 mole NaOH) = 0.04649 moles H2SO4-- Sulfuric acid limits and, 0.04648 moles of sodium hydroxide are in excess.