1.5
- your welcome
To determine the number of moles, use the formula: moles = mass / molar mass. The molar mass of C2H5OH (ethanol) is approximately 46.07 g/mol. Therefore, 11.5g of C2H5OH represents approximately 0.25 moles.
To calculate the number of grams of C6H12O6 needed to form 7.50g of C2H5OH, you need to consider the stoichiometry of the reaction between these two compounds. The balanced equation for the conversion of C6H12O6 to C2H5OH is C6H12O6 -> 2 C2H5OH. This means that for every mole of C6H12O6, you get 2 moles of C2H5OH. You can then use the molar mass of each compound to convert grams to moles, and then determine the grams of C6H12O6 needed to form 7.50g of C2H5OH.
To find the mole fraction of ethanol (C2H5OH), you first need to calculate the moles of ethanol in the solution. Then, calculate the total moles of all components in the solution. Finally, divide the moles of ethanol by the total moles to get the mole fraction. In this case, since the solution is 50% ethanol by mass, you can assume 50 g of the solution to make calculations simpler.
27.4 g H2O x 1 mole/18 g = 1.52 moles
To convert moles to grams, you need to use the molar mass of ethyl alcohol. The molar mass of ethyl alcohol (C2H5OH) is approximately 46.07 g/mol. Therefore, 1.36 mol of ethyl alcohol would be 1.36 mol x 46.07 g/mol = 62.59 grams.
To find the number of moles of ethanol (C2H5OH) in 16.0 g, first calculate its molar mass. The molar mass of C2H5OH is approximately 46.07 g/mol. Using the formula: moles = mass (g) / molar mass (g/mol), we have moles = 16.0 g / 46.07 g/mol, which equals approximately 0.347 moles of ethanol.
To determine the number of moles, use the formula: moles = mass / molar mass. The molar mass of C2H5OH (ethanol) is approximately 46.07 g/mol. Therefore, 11.5g of C2H5OH represents approximately 0.25 moles.
115/7=16.42mol
For this you need the atomic (molecular) mass of C2H5OH. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. C2H5OH= 46.1 grams1.271 grams C2H5OH / (46.1 grams) = .0276 moles C2H5OH
To calculate the number of grams of C6H12O6 needed to form 7.50g of C2H5OH, you need to consider the stoichiometry of the reaction between these two compounds. The balanced equation for the conversion of C6H12O6 to C2H5OH is C6H12O6 -> 2 C2H5OH. This means that for every mole of C6H12O6, you get 2 moles of C2H5OH. You can then use the molar mass of each compound to convert grams to moles, and then determine the grams of C6H12O6 needed to form 7.50g of C2H5OH.
The mass of 2 moles of ethyl alcohol would be 92,14 grams.
79c
80c
88c
To find the number of moles in 508g of ethanol (C2H5OH), first calculate the molar mass of ethanol: 2(12.01) + 6(1.01) + 1(16.00) = 46.08 g/mol. Next, divide the given mass by the molar mass to find the number of moles: 508g / 46.08 g/mol ≈ 11 moles.
35 c
80c