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Wiki User
∙ 12y ago
Wiki User
∙ 8y agoTo calculate the moles in 11.5 g of C2H5OH (ethanol), you first need to know the molar mass of C2H5OH. This is obtained by adding the mass of the elements: C = 2x12 = 24; H = 6x1 = 6; O = 16.
Thus, 24 + 6+ 16 = 46 g/mole. Then, 11.5 g x 1 mole/46g = 0.25 moles
Wiki User
∙ 6y ago1 gram of C2H5OH is equivalent to 0,0217 moles.
Owen Wang
How many moles are represented by 11.5g of C2H5OH?
Wiki User
∙ 13y ago1.5 moles
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How many grams of C6H12O6 are needed to form 7.50g of C2H5OH?
14.7 g
How many moles does 3.80 g Zn have?
3,80 g Zn have 0,058 moles.
How many moles of argon are in 24.7 g of argon?
Moles = weight in g / atomic weight. So moles in 24.7 g of Ar = 24.7 / 39.948 = 0.62 moles
How many moles of CCl4 are there in 56 g?
The answer is 0,364 moles.
How many moles are in 19.2 g of CS2?
The answer is 0,253 moles.
How many moles are in 115 g of Li?
115/7=16.42mol
The formula for ethyl alcohol is C2H5OH. The mass of 2 moles of ethyl alcohol would be how many grams?
The mass of 2 moles of ethyl alcohol would be 92,14 grams.
What is the boiling point of a solution of 25.0 g of c3h8o3 in 250 g c2h5oh kb for c2h5oh is 1.19ºcm and the boiling point of c2h5oh is 78ºc?
79c
What is the boiling point of a solution of 235.0 g of c2h6o2 in 450 g c2h5oh kb for c2h5oh is 1.19ºcm and the boiling point of c2h5oh is 78ºc?
80c
What is the boiling point of a solution of 125.0 g of c6h12o6 in 350 g c2h5oh kb for c2h5oh is 1.19ºcm and the boiling point of c2h5oh is 78ºc?
88c
What is the boiling point of a solution of 125.0 g of c6h12o6 in 350 g c2h5oh kb for c2h5oh is 1.19ºc m and the boiling point of c2h5oh is 78ºc?
80c
What is the boiling point of a solution of 1250 g of c6h12o6 in 350 g c2h5oh kb for c2h5oh is 119cm and the boiling point of c2h5oh is 78c?
35 c
What is the boiling point of a solution of 125.0 g of c6h12o6 in 350 g c2h5oh kb for c2h5oh is 1.19cm and the boiling point of c2h5oh is 78c?
80 degrees Celsius
How many grams of C6H12O6 are needed to form 7.50g of C2H5OH?
14.7 g
How many moles does 3.80 g Zn have?
3,80 g Zn have 0,058 moles.
If you have g of beryllium how many moles is this equivalent to?
The formula is: number of moles = g Be/9,012.
How many moles of argon are in 24.7 g of argon?
Moles = weight in g / atomic weight. So moles in 24.7 g of Ar = 24.7 / 39.948 = 0.62 moles
