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How many moles of Li atoms are in 10.56grams of Li?
How many lithium atoms are in 10.56 g of lithium
How many grams of Li3N can be formed from 1.75 moles of Li?
20,32 g of lithium nitride can be obtained.
What is the number of moles of 27.6 g of lithium (li)?
3.977 mol
How many moles are contained in 25.0 grams of lithium?
15g Li * (1mol Li / 6.941g Li) = 2.16 mol Li
How many grams are in 0.0864 moles of lithium?
To convert moles to grams, you need to know the molar mass of lithium, which is approximately 6.94 g/mol. Multiplying the number of moles (0.0864 mol) by the molar mass (6.94 g/mol) gives you approximately 0.6 grams of lithium.
How many LI atoms are contained in 97.9 of LI?
I assume you mean 97.9 grams lithium. 97.9 grams lithium (1 mole Li/6.941 grams)(6.022 X 10^23/1 mole Li) = 8.49 X 10^24 atoms of lithium ---------------------------------------
How much would 5.0 moles of lithium weigh in gram?
5.0 mol Li * 6.941 g/mol Li = 34.705 = 35 g Lithium
What is the number of moles of 27.6 g of lithium Li?
To find the number of moles of lithium in 27.6 g, you first need to determine the molar mass of lithium, which is approximately 6.94 g/mol. Then, divide the given mass by the molar mass to obtain the number of moles. In this case, 27.6 g ÷ 6.94 g/mol ≈ 3.98 moles of lithium.
A student weighed 0.550 g of lithium chloride LiCl to use in a reaction How many moles is this?
To calculate the number of moles of lithium chloride (LiCl) in 0.550 g, you need to divide the mass by the molar mass of LiCl. The molar mass of LiCl is approximately 42.39 g/mol (6.94 g/mol for Li and 35.45 g/mol for Cl). Therefore, 0.550 g of LiCl is approximately 0.013 moles.
What is the mass of 21.3 mol Li?
To find the mass of 21.3 moles of lithium (Li), you can use the molar mass of lithium, which is approximately 6.94 g/mol. Multiply the number of moles by the molar mass: (21.3 , \text{mol} \times 6.94 , \text{g/mol} = 147.58 , \text{g}). Therefore, the mass of 21.3 moles of lithium is approximately 147.58 grams.
If you have g of beryllium how many moles is this equivalent to?
The formula is: number of moles = g Be/9,012.
What mass of water is needed to react with 32.9 Li3N?
To determine the mass of water needed to react with 32.9 g of Li₃N, we first need to balance the chemical equation for the reaction between Li₃N and water. The balanced equation is: 2Li₃N + 3H₂O → 6LiOH + NH₃ From the equation, we see that 3 moles of water are needed to react with 2 moles of Li₃N. So, first calculate the moles of Li₃N in 32.9 g, then use the mole ratio from the balanced equation to find the moles of water needed, and finally convert the moles of water to grams.
