In each mole of ethanol there are two moles of carbon atoms. One mole of carbon atoms is required to form one mole of carbon dioxide, so two moles will form two moles. Thus each mole of ethanol completely combusted will form two moles of carbon dioxide.
To determine the number of moles, use the formula: moles = mass / molar mass. The molar mass of C2H5OH (ethanol) is approximately 46.07 g/mol. Therefore, 11.5g of C2H5OH represents approximately 0.25 moles.
1.5 - your welcome
The balanced equation for the combustion of ethane (C2H6) is: 2C2H6 + 7O2 -> 4CO2 + 6H2O From the equation, for every 2 moles of ethane burned, 4 moles of CO2 are produced. Therefore, if 5.60 mol of ethane are burned, then (5.60 mol / 2 mol ethane) * 4 mol CO2 = 11.2 mol of CO2 are produced.
To calculate the number of grams of C6H12O6 needed to form 7.50g of C2H5OH, you need to consider the stoichiometry of the reaction between these two compounds. The balanced equation for the conversion of C6H12O6 to C2H5OH is C6H12O6 -> 2 C2H5OH. This means that for every mole of C6H12O6, you get 2 moles of C2H5OH. You can then use the molar mass of each compound to convert grams to moles, and then determine the grams of C6H12O6 needed to form 7.50g of C2H5OH.
When 1.0 mole of O2 is completely consumed in the reaction to form NO, 1.0 mole of NO is produced since the balanced equation for the reaction is 2 O2 + 2 N2 -> 2 NO. This means that the mole ratio between O2 and NO is 1:1.
6,49 moles of water are obtained.
To determine the number of moles, use the formula: moles = mass / molar mass. The molar mass of C2H5OH (ethanol) is approximately 46.07 g/mol. Therefore, 11.5g of C2H5OH represents approximately 0.25 moles.
1.5 - your welcome
If burnt with excess O2 then 19.65 (=3*6.55) mole H2O
30 moles
To determine the number of moles of carbon dioxide produced when hexane is burned, we need to consider the balanced chemical equation for the combustion of hexane, which is C6H14 + 19/2 O2 -> 6 CO2 + 7 H2O. From the balanced equation, we can see that for every mole of hexane burned, 6 moles of carbon dioxide are produced. Therefore, if 84.4 moles of hexane is burned, 6 * 84.4 = 506.4 moles of carbon dioxide would be produced.
2
To find the number of moles of ethanol (C2H5OH) in 16.0 g, first calculate its molar mass. The molar mass of C2H5OH is approximately 46.07 g/mol. Using the formula: moles = mass (g) / molar mass (g/mol), we have moles = 16.0 g / 46.07 g/mol, which equals approximately 0.347 moles of ethanol.
The balanced equation for the combustion of ethane (C2H6) is: 2C2H6 + 7O2 -> 4CO2 + 6H2O From the equation, for every 2 moles of ethane burned, 4 moles of CO2 are produced. Therefore, if 5.60 mol of ethane are burned, then (5.60 mol / 2 mol ethane) * 4 mol CO2 = 11.2 mol of CO2 are produced.
For this you need the atomic (molecular) mass of C2H5OH. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. C2H5OH= 46.1 grams1.271 grams C2H5OH / (46.1 grams) = .0276 moles C2H5OH
To calculate the number of grams of C6H12O6 needed to form 7.50g of C2H5OH, you need to consider the stoichiometry of the reaction between these two compounds. The balanced equation for the conversion of C6H12O6 to C2H5OH is C6H12O6 -> 2 C2H5OH. This means that for every mole of C6H12O6, you get 2 moles of C2H5OH. You can then use the molar mass of each compound to convert grams to moles, and then determine the grams of C6H12O6 needed to form 7.50g of C2H5OH.
When 1.0 mole of O2 is completely consumed in the reaction to form NO, 1.0 mole of NO is produced since the balanced equation for the reaction is 2 O2 + 2 N2 -> 2 NO. This means that the mole ratio between O2 and NO is 1:1.