35,0 mL of a 5,50 M KOH solution contain 10,8 g KOH.
To find the number of moles of sulfuric acid in the solution, multiply the volume of the solution (in liters) by the molarity. First, convert 500 mL to liters by dividing by 1000 (500 mL = 0.5 L). Then, multiply 0.5 L by 0.324 mol/L to get 0.162 moles of sulfuric acid in 500 mL of the 0.324 M solution.
The molarity of the solution is calculated using the formula: Molarity (M) = moles of solute / liters of solution. First, convert 500 mL to liters by dividing by 1000 (500 mL = 0.5 L). Then, plug in the values: M = 2.5 moles / 0.5 L = 5 M. Hence, the molarity of the solution is 5 M.
Molarity = moles of solute/Liters of solution ( 75.0 ml = 0.075 Liters ) Algebraically manipulate, moles of solute = Liters of solution * Molarity Moles KMnO4 = (0.075 Liters)(0.0950 M) = 7.13 X 10 -3 moles KMnO4 ------------------------------------
To determine the grams of solute in a solution, you need to know the molar mass of the solute. Multiply the molarity of the solution by the volume in liters to get the number of moles, then multiply by the molar mass to get the grams. In this case, for 2 moles of solute in 500 cm3 (which is 0.5 L), the mass of the solute would be 2 moles/L * 0.5 L * molar mass of solute in g/mol.
To calculate the molarity of the solution, first convert the mass of HCl to moles using its molar mass. Then, divide the number of moles by the volume of the solution in liters (500 cm3 = 0.5 L) to get the molarity.
The answer is 1,5 moles.
The answer is 0,1 mol.
To find the number of moles of sulfuric acid in the solution, multiply the volume of the solution (in liters) by the molarity. First, convert 500 mL to liters by dividing by 1000 (500 mL = 0.5 L). Then, multiply 0.5 L by 0.324 mol/L to get 0.162 moles of sulfuric acid in 500 mL of the 0.324 M solution.
The molarity of the solution is calculated using the formula: Molarity (M) = moles of solute / liters of solution. First, convert 500 mL to liters by dividing by 1000 (500 mL = 0.5 L). Then, plug in the values: M = 2.5 moles / 0.5 L = 5 M. Hence, the molarity of the solution is 5 M.
The 0.5M and 2M refer to moles per liter (of solution). Volume of final solution is 2.5 L + 500 mL = 2.5 L + 0.5 L = 3.0 L. So find out how many moles the final solution has and divide by 3.0L.First solution (0.5 moles/liter)*(2.5 liter) = 1.25 moles2nd solution (2 moles/liter)*(0.5 liter) = 1 moleMolarity: (1.25 mole + 1 mole)/(3.0 liter) = 0.75 moles/liter = 0.75 M
500ml = 500cm3 = 0.5dm3 0.250M = 0.250mol/dm3 number of moles = molarity x volume number of moles = 0.250mol/dm3 x 0.5dm3 = 0.125mol 0.125mol of NaCl is needed to prepare the required solution.
Molarity = moles of solute/Liters of solution ( 75.0 ml = 0.075 Liters ) Algebraically manipulate, moles of solute = Liters of solution * Molarity Moles KMnO4 = (0.075 Liters)(0.0950 M) = 7.13 X 10 -3 moles KMnO4 ------------------------------------
To determine the grams of solute in a solution, you need to know the molar mass of the solute. Multiply the molarity of the solution by the volume in liters to get the number of moles, then multiply by the molar mass to get the grams. In this case, for 2 moles of solute in 500 cm3 (which is 0.5 L), the mass of the solute would be 2 moles/L * 0.5 L * molar mass of solute in g/mol.
Need moles aluminum oxide first. 51 grams Al2O3 (1 mole Al2O3/101.96 grams) = 0.5002 moles Al2O3 ======================Now, Molarity = moles of solute/Liters of solution (500 ml = 0.500 Liters ) Molarity =0.5002 moles Al2O3/0.500 Liters = 1.0 M Al2O3 solution ----------------------------
M= moles in solution/liters so plug in what you know 3.0M of KCl solution = moles in solution/ 2.0L multiply both sides by 2.0L moles solute = 1.5 moles KCl so you need 1.5 moles KCl to prepare the solution
To calculate the molarity of the solution, first convert the mass of HCl to moles using its molar mass. Then, divide the number of moles by the volume of the solution in liters (500 cm3 = 0.5 L) to get the molarity.
Molarity (M) is defined as moles of solute/liters of solution. Assuming the final volume is 500 ml (0.5 liters), then M = 1.2 moles/0.5 liters = 2.4 M