The answer is 0,0108 moles.
3.3 moles of K2S 3.3 moles of S-2 6.6 moles of K+1
2.60 moles There are 2 moles of K in K2SO4. the total moles times two (1.3 x 2) is 2.60 moles.
To convert from moles to grams, we need to use the molar mass of the element. The molar mass of potassium (K) is approximately 39.10 g/mol. So, for 1.90 moles of K, the mass would be 1.90 moles * 39.10 g/mol = 74.29 grams.
In the K2SO4 equation, SO4 is not a cation since it consists of negatively charged ions. So K+ is the only cation, and since there are two of them then it is 2 mole K+ per mole K2SO4 . So 2 x 1.55 = 3.10 mol K+
The balanced chemical equation for the reaction between water (H2O) and potassium (K) is: 2K + 2H2O -> 2KOH + H2. 1 mole of potassium (K) reacts with 1 mole of water (H2O). Therefore, 7.54 moles of potassium would react with 7.54 moles of water.
If you have 0.5 moles of K₂CO₃, then you simply have 0.5 moles of K₂CO₃. The quantity of moles is a direct measurement, so there are no additional calculations needed. Therefore, the answer is 0.5 moles of K₂CO₃.
3.3 moles of K2S 3.3 moles of S-2 6.6 moles of K+1
0.3 moles K (6.022 X 10^23/1mol K) = 1.8 X 10^23 atoms of K
The answer is 0,125 moles.
0.125 moles
2.60 moles There are 2 moles of K in K2SO4. the total moles times two (1.3 x 2) is 2.60 moles.
To produce potassium nitride (K₃N), the balanced chemical equation is 6 K + N₂ → 2 K₃N. This indicates that 6 moles of potassium are required to produce 2 moles of potassium nitride. Therefore, to produce 2.0 moles of K₃N, you would need 6 moles of potassium.
The answer is 0,19 moles.
To convert from moles to grams, we need to use the molar mass of the element. The molar mass of potassium (K) is approximately 39.10 g/mol. So, for 1.90 moles of K, the mass would be 1.90 moles * 39.10 g/mol = 74.29 grams.
In the K2SO4 equation, SO4 is not a cation since it consists of negatively charged ions. So K+ is the only cation, and since there are two of them then it is 2 mole K+ per mole K2SO4 . So 2 x 1.55 = 3.10 mol K+
1000 Kelvin = 1,340.33 Fahrenheit
According to the reaction (4 \text{K} + \text{O}_2 \rightarrow 2 \text{K}_2\text{O}), 4 moles of potassium produce 2 moles of potassium oxide (K2O). Thus, the mole ratio of potassium to K2O is 4:2, or 2:1. If 1.52 moles of potassium are used, the number of moles of K2O formed can be calculated as (1.52 , \text{moles K} \times \frac{2 , \text{moles K2O}}{4 , \text{moles K}} = 0.76 , \text{moles K2O}). Therefore, 0.76 moles of potassium oxide will be formed.