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The mass of 1 mole of an element is its atomic weight on the Periodic Table in grams.
1g = 1000mg
The mass of 1 mole of Kr = 83.80g Kr
Convert mg Kr to g Kr.
398mg Kr x (1g/1000mg) = 0.398g Kr
Convert g Kr to mol Kr.
0.398g Kr x (1mol Kr/83.80g Kr) = 4.75x10-3mol Kr
What else can I help you with?
What mass in g does 7.98 moles of Kr have?
7.98 moles of Kr have 668,708 g.
What mass does 3.99 moles of Kr have?
To find the mass of 3.99 moles of Kr (krypton), you need to multiply the number of moles by the molar mass of Kr. The molar mass of Kr is approximately 83.80 g/mol. So, the mass of 3.99 moles of Kr would be approximately 334.60 grams.
How many atoms of krypton are in 2.50 moles of Kr gas?
The mass in grams of KBr contained in 2.50 moles of the compound is 2.5 times the sum of the gram atomic masses of hydrogen and bromine, or 2.50(1.008 + 79.904) or 202 grams, to the justified number of significant digits.
What volume will 0.405 g of krypton gas occupy at STP?
First we need the moles of krypton gas. Monoatomic gas.0.405 grams Kr (1 mole Kr/83.80 grams)= 0.004833 moles krypton gas======================Now the ideal gas equation.PV = nRT(1 atm)(X volume) = (0.004833 moles Kr)(0.08206 L*atm/mol*K)(298.15 K)= 0.118 Liters of krypton gas--------------------------------------
How many moles of kr g are there in .555 liters of the gas at .918 ATM and 25 degrees Celsius?
To find the number of moles of krypton gas, we first need to convert the volume from liters to moles using the ideal gas law. Then, we use the equation n = PV / RT where P is pressure, V is volume, R is the ideal gas constant, and T is temperature in Kelvin. From there, we can calculate the number of moles present in the given conditions.
How many moles are in 0.377 grams of Kr?
0.377 grams of Kr is equal to 0,0045 moles.
How many mole of kr are contained in 398 mg of kr?
The mass of 1 mole of an element is its atomic weight on the Periodic Table in grams.1g = 1000mgThe mass of 1 mole of Kr = 83.80g KrConvert mg Kr to g Kr.398mg Kr x (1g/1000mg) = 0.398g KrConvert g Kr to mol Kr.0.398g Kr x (1mol Kr/83.80g Kr) = 4.75x10-3mol Kr
What mass in g does 7.98 moles of Kr have?
7.98 moles of Kr have 668,708 g.
What mass (in g) does 7.98 moles of Kr have?
7.98 moles of Kr have 668,708 g.
What mass in g does 3.99 moles of Kr have?
3,99 moles of Kr have 334,35 g.
What mass in g 3.99 moles of Kr have?
3,99 moles of Kr is equal to 334,354 g.
How many grams are contained in 4.56 moles of krypton Kr?
4.56 moles Kr x 83.798 g/mole = 382.119 grams = 382 grams (to 3 significant figures)NOTE: You should not use more than 3 significant figures since 4.56 moles limits the precision. Thus the answers of 381.66g and 382.1188 g are incorrect.
How many Kr atoms are there in 2.51 moles of Kr?
The number of atoms is 15,11.10EX23.
What mass does 3.99 moles of Kr have?
To find the mass of 3.99 moles of Kr (krypton), you need to multiply the number of moles by the molar mass of Kr. The molar mass of Kr is approximately 83.80 g/mol. So, the mass of 3.99 moles of Kr would be approximately 334.60 grams.
How many moles are in 1.7 times 10 to the 25th power atoms of krypton?
1 mole Kr = 6.022 x 1023 atoms 1.7 x 1025 Kr atoms x (1 mole Kr)/(6.022 x 1023 Kr atoms) = 28 moles Kr (rounded to two sig figs)
How do you convert 1.29 mol Kr to a number of atoms?
Just multiply the moles of Kr by Avogadro's number. Formal set up.1.29 moles Kr (6.022 X 1023/1 mole Kr)= 7.77 X 1023 atoms of krypton====================
How many moles F2 are required to produce 3.0 moles KrF6 in the equation Kr plus 3F2 producing KrF6?
Given the balanced equation Kr + 3F2 --> KrF6 In order to find how many moles of F2 are needed to produce 3.0 moles of KrF6, we must convert from moles to moles (mol --> mol conversion). 3.0 mol KrF6 * 3 molecules F2 = 9.0 mol F2 --------- 1 molecule F2
