Also 0,3 moles nitric oxide.
The balanced reaction equation is 4Al + 3O2 -> 2Al2O3. Therefore, 3 moles of O2 reacts with 4 moles of Al to form 2 moles of Al2O3. Since 0.78 mol of O2 is reacted, the number of moles of Al2O3 formed can be calculated using the stoichiometry of the reaction.
2Cl2 + 7O2 --> 2Cl2O7So for every 2 moles of dichlorine heptoxide formed, 7 moles of oxygen are reacted.69.1 moles Cl2O7 * (7 moles O2 / 2 moles Cl2O7) = 241.85 moles O2
The balanced chemical reaction equation says that you get 3 moles of O2.m O2 = ( n O2 ) ( M O2 )m O2 = ( 3 mol O2 ) ( 32.00 g O2 / mol O2 = 96 g O2
Using the molar mass of nh3, we find that we have 2.5 moles of nh3. Since 3 moles of h2o are produced per 2 moles of nh3, we see that we will produce 3.75 moles of h2o. This is equivalent to around 3.79 g.
Only when 5.5 mole O2 react with 11 mole H2, then 11 mole H2O are formed.
The balanced reaction equation is 4Al + 3O2 -> 2Al2O3. Therefore, 3 moles of O2 reacts with 4 moles of Al to form 2 moles of Al2O3. Since 0.78 mol of O2 is reacted, the number of moles of Al2O3 formed can be calculated using the stoichiometry of the reaction.
From the balanced chemical equation, 4 moles of KOH produce 1 mole of O2. Given that there are 6.21 moles of KOH, we can set up a ratio: (6.21 moles KOH) x (1 mole O2 / 4 moles KOH) = 1.5525 moles O2. Finally, using molar mass of oxygen (O2) which is 32 g/mol, we find that 1.5525 moles of O2 is equal to 49.68 grams of O2.
In the reaction 4 moles of aluminum will react with 3 moles of oxygen to form 2 moles of aluminum oxide. Since we have 2.0 moles of aluminum, we would need (2.0 mol Al) x (3 mol O2 / 4 mol Al) = 1.5 moles of O2 to react with it.
2Cl2 + 7O2 --> 2Cl2O7So for every 2 moles of dichlorine heptoxide formed, 7 moles of oxygen are reacted.69.1 moles Cl2O7 * (7 moles O2 / 2 moles Cl2O7) = 241.85 moles O2
The answer is 2 moles.
The most straightforward reaction for the formation of SO3 from SO2 is 2 SO2 + O2 => 2 SO3. If this is the actual reaction for the formation, 3 moles of SO3 are formed from 3 moles of SO2.
The balanced chemical reaction equation says that you get 3 moles of O2.m O2 = ( n O2 ) ( M O2 )m O2 = ( 3 mol O2 ) ( 32.00 g O2 / mol O2 = 96 g O2
Using the molar mass of nh3, we find that we have 2.5 moles of nh3. Since 3 moles of h2o are produced per 2 moles of nh3, we see that we will produce 3.75 moles of h2o. This is equivalent to around 3.79 g.
Only when 5.5 mole O2 react with 11 mole H2, then 11 mole H2O are formed.
4
The answer is 10 moles of carbon monoxide.2 C + O2 = 2 CO
3 moles of O, so that must be 6 moles of O2