How many moles of carbon are needed to react with 580 g of hematite?

Answer 1

Which carbon are u talking about? Carbon in coke is first oxidised to form carbon dioxide - C(s) + O2(g) -> CO2(g). Limestone is decomposed by heat to form calcium oxide and carbon dioxide. CaCO3 -> CaO(s) + CO2(g). The carbon dioxide produced in the two reactions are reduced by carbon in coke to form carbon monoxide. CO2(g) + C(s) -> 2CO(g). The carbon monoxide then reacts with iron (III) oxide in haematite to form iron and carbon dioxide. Fe2O3(s) + 3CO(g) -> 2Fe(l) + 3CO2(g). If ur referring to this last reaction above, 520grams of iron (III) oxide react with 210grams of carbon dioxide. Mol. of Fe203 reacted -> (520/104) = 5mol. Mol of carbon dioxide reacted -> 5 X 3 = 15. Mass of carbon dioxide reacted -> 15 X 14 = 210g

Answer 2

The equation for the reduction of hematite is 2 Fe2O3 + 3 C = 4 Fe + 3 CO2. Every 2 moles of hematite requires 3 moles of carbon. Hematite has a molar mass of 159.69 grams per mole, so there is 3.63 moles. This means there are 5.45 moles of carbon needed.

Answer 3

First, determine the molar mass of hematite (Fe2O3) by adding the molar masses of iron (Fe) and oxygen (O). Next, find the number of moles of hematite in 580 g using its molar mass. Then, use the balanced chemical equation representing the reaction to determine the mole ratio of carbon to hematite. Finally, use the mole ratio to find the number of moles of carbon needed to react with the calculated moles of hematite.