4Mg + 2O2 ---> 4MgO
4 moles of MgO is formed.
I assume you mean this reaction.
2Mg + O2 -> 2MgO
( we can assume Mg limits )
as you can see they are one to one ( Mg and MgO ) so.........
3.5 moles MgO
3 moles of magnesium are needed.
1.75
Assuming a decomposition reaction with this equation: 2KClO3(s) --> 2KCl(s) + 3O2(g), the ratio is 2:3, and if you produce 15mol O2, then 10mol potassium chlorate are needed.
Since there are no subscripts, there is .800 moles of Oxygen atoms and .800 moles of Magnesium because there is .800 moles of the compound.
The chemical reactin is:2 KClO3 = 2 KCl + 3 O24 moles of potassium chlorate produce 6 moles oxygen.
This is based on calculations too. It contains 18 hydrogen moles.
A sample of 56,4 of magnesium is equal to 2,32 moles.
800 g oxygen are needed.
Four moles of potassium chlorate are needed.
The formula for magnesium oxide is MgO, showing that each formula unit of magnesium oxide contains one mole of magnesium ions. Therefore, if there is ample oxygen available, 4 moles of magnesium will form 4 moles of magnesium oxide.
Balanced Formula:2Mg + O2 --> 2MgOMole ratio:2 : 1 : 2Givens:.486 g oxygen.738 g magnesium24.3 g = atomic mass of magnesium16.0 g = atomic mass of oxygen40.3 g = molecular mass of magnesium oxideFind the amount (in moles) of Magnesium oxide that oneelement will make:(.486 g O) / (16.0 g O) × (2 moles MgO)= .0608 moles MgO(.783 g Mg) / (24.3 g Mg) = .0322 moles MgOThere is less MgO produced with magnesium than oxygen; therefore, magnesium is the limiting reactant and the oxygen is the excess reactant. The magnesium determines how much Magnesium oxide is produced. It would be good to get .0608 moles of MgO, but there isn't enough magnesium. So the amount of MgO produced will be determined on the amount of Magnesium.Convert moles of MgO produced with the amount of oxygen to grams:.0322 mol MgO (40.3 g) = 1.30 grams of MgO produced--------------------------------------------------------------------------------------------------------You will need 3 moles of oxygen if you start with six moles of magnesium. This will allow you to produce 6 moles of magnesium oxide.Source: (e2020)
From the formula, you have 2 atoms of Magnesium combine with one oxygen molecule to form 2 molecules of magnesium oxide. So when 4 magnesium atoms combine with two molecules of oxygen you get 4 magnesium oxide molecules. So from 4 moles of magnesium you get 4 moles of Magnesium oxide.
2Mg + O2 -----> 2MgO So two moles of magnesium oxide are formed if x moles of magnesium are allowed to react with only 1 mole of oxygen molecules. The oxygen has become the limiting ingredient.
8,75 moles of oxygen are needed.
Assuming a decomposition reaction with this equation: 2KClO3(s) --> 2KCl(s) + 3O2(g), the ratio is 2:3, and if you produce 15mol O2, then 10mol potassium chlorate are needed.
Since there are no subscripts, there is .800 moles of Oxygen atoms and .800 moles of Magnesium because there is .800 moles of the compound.
The chemical reactin is:2 KClO3 = 2 KCl + 3 O24 moles of potassium chlorate produce 6 moles oxygen.
2CsClO4 -> 2Cs + Cl2 + 4O2 2.7 moles O2 (2 moles CsClO4/4 mole O2) = 1.4 mole CsClO4 needed
16,875 moles of oxygen are needed.