Each mole of PbO2 contains 2 moles of oxygen (O). Thus there would be 5.43x2 = 10.86 moles O.
Each mole of water (H2O) contains 1 mole of O, so from 10.86 moles of O you could get 10.86 moles of H2O.
Formula unit is (molar mass) * (6.0221421*10^23)Molar mass of PbO2 is239.2089 g/molMolar mass of 50.0g of PbO2 is 50/239.2089 g/molFormula unit of PbO2 is ( 50g/239.2089 g/mol) *(6.0221421*10^23)=(0.20902232316606948988938120613405mol) *(6.0221421*10^23units/mol)=1.2587621321781923665883669044087*10^23unitsor approx. 1,26.1023 formula units.
Lead dioxide (PbO2) is typically a dark brown or black color.
PbO2 is lead(IV) oxide.
Lead Dioxide or Lead IV Oxide
PbO2 is a stronger oxidizing agent compared to PbO because PbO2 has a higher oxidation state of +4 for lead, allowing it to accept more electrons during a redox reaction. This makes PbO2 more likely to cause other substances to be oxidized.
Formula unit is (molar mass) * (6.0221421*10^23)Molar mass of PbO2 is239.2089 g/molMolar mass of 50.0g of PbO2 is 50/239.2089 g/molFormula unit of PbO2 is ( 50g/239.2089 g/mol) *(6.0221421*10^23)=(0.20902232316606948988938120613405mol) *(6.0221421*10^23units/mol)=1.2587621321781923665883669044087*10^23unitsor approx. 1,26.1023 formula units.
The product for the reaction between PbO2 and O2 is PbO2.
The traditional name for PbO2 is lead dioxide.
PbO2 is lead(IV) oxide.
Lead dioxide (PbO2) is typically a dark brown or black color.
Lead Dioxide or Lead IV Oxide
PbO2 is a stronger oxidizing agent compared to PbO because PbO2 has a higher oxidation state of +4 for lead, allowing it to accept more electrons during a redox reaction. This makes PbO2 more likely to cause other substances to be oxidized.
2PbS + 3O2 ----> 2PbO + 2SO2
The reaction is balanced since 2 moles of PbO2 yield 2 moles of PbO and 1 mole of O2. The law of conservation of mass is upheld with the same number of atoms of each element on both sides of the reaction.
The formula for plumbous oxide is PbO.
The balanced chemical equation for the given reaction is: PbO2 + PbO -> 2PbO + O2 Coefficients: 1 PbO2, 1 PbO, 2 PbO, 1 O2.
The ionic chemical formula of lead(IV) oxide is: (Pb)4+ + 2 O-.