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To find the mass of 3.7 moles of PbO2 (lead(IV) oxide), you first need to calculate its molar mass. The molar mass of PbO2 is approximately 239.2 g/mol (lead = 207.2 g/mol, oxygen = 16 g/mol × 2). Therefore, the mass can be calculated as:
Mass = moles × molar mass = 3.7 mol × 239.2 g/mol ≈ 884.04 grams.
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What is the mass of the 3.7 mol pb02?
To find the mass of 3.7 moles of PbO2 (lead(IV) oxide), we first need to calculate its molar mass. The molar mass of PbO2 is approximately 207.2 g/mol (for Pb) + 2 × 16.0 g/mol (for O) = 239.2 g/mol. Therefore, the mass of 3.7 moles of PbO2 is 3.7 mol × 239.2 g/mol = 884.04 grams.
What is the percent of lead in lead IV oxide Or how do i calculate it?
86.62(8)%The molar masses of the constituent elements must be known.M(Pb) = 2.072(1) x 102 gmol-1M(O) = 1.59994(3) x 10 gmol-1From these and their respective molar ratios in the compound, the total molar mass of the compound must be calculated.M(PbO2) = M(Pb) + 2M(O)M(PbO2) = (2.072 x 10 gmol-1 + 2(1.59994 gmol-1)) x 10M(PbO2) = 2.392(1) x 102 gmol-1From the molar mass of the element in question and its ratio, and the compound, their total masses present in one mole of compound must be calculated.m = nMm(Pb) = 1 mol x 2.072 x 102 gmol-1m(Pb) = 2.072(1) x 102 gm(PbO2) = 1 mol x 2.392(1) x 102 g (always 1 mole)m(PbO2) = 2.392(1) x 102 gFrom these, the percentage of the element in question present in the compound can be calculated.m(Pb) x 100%/m(PbO2) = 2.072 g x 100%/2.392 gm(Pb) x 100%/m(PbO2) = 86.62(8)%
What is the mass of 0.50 mol of aluminum foil?
To find the mass of 0.50 mol of aluminum foil, we first need the molar mass of aluminum, which is approximately 27 g/mol. Therefore, the mass can be calculated using the formula: mass = moles × molar mass. For 0.50 mol of aluminum, the mass would be 0.50 mol × 27 g/mol = 13.5 grams.
Calculate NaCl in atomic mass?
By adding up the mass numbers of Na (23) and Cl (35 or 37). It is determined by the total of numbers of protons (11 and 17 respectively) and of neutrons (12 and 18 or 20), however it is not a sensible exercition to do, you cannot calculate anything with this figure.
Calculate the mass in grams of 2.60 mol of potassium chloride (KCl)?
To calculate the mass of 2.60 mol of potassium chloride (KCl), first determine its molar mass. The molar mass of KCl is approximately 74.55 g/mol (39.10 g/mol for K and 35.45 g/mol for Cl). Thus, the mass can be calculated using the formula: mass = moles × molar mass. Therefore, the mass of 2.60 mol of KCl is 2.60 mol × 74.55 g/mol = 193.83 grams.
What is the mass of the 3.7 mol pb02?
To find the mass of 3.7 moles of PbO2 (lead(IV) oxide), we first need to calculate its molar mass. The molar mass of PbO2 is approximately 207.2 g/mol (for Pb) + 2 × 16.0 g/mol (for O) = 239.2 g/mol. Therefore, the mass of 3.7 moles of PbO2 is 3.7 mol × 239.2 g/mol = 884.04 grams.
How many formula units are in 50.0 g of PbO2?
Formula unit is (molar mass) * (6.0221421*10^23)Molar mass of PbO2 is239.2089 g/molMolar mass of 50.0g of PbO2 is 50/239.2089 g/molFormula unit of PbO2 is ( 50g/239.2089 g/mol) *(6.0221421*10^23)=(0.20902232316606948988938120613405mol) *(6.0221421*10^23units/mol)=1.2587621321781923665883669044087*10^23unitsor approx. 1,26.1023 formula units.
What is the percent of lead in lead IV oxide Or how do i calculate it?
86.62(8)%The molar masses of the constituent elements must be known.M(Pb) = 2.072(1) x 102 gmol-1M(O) = 1.59994(3) x 10 gmol-1From these and their respective molar ratios in the compound, the total molar mass of the compound must be calculated.M(PbO2) = M(Pb) + 2M(O)M(PbO2) = (2.072 x 10 gmol-1 + 2(1.59994 gmol-1)) x 10M(PbO2) = 2.392(1) x 102 gmol-1From the molar mass of the element in question and its ratio, and the compound, their total masses present in one mole of compound must be calculated.m = nMm(Pb) = 1 mol x 2.072 x 102 gmol-1m(Pb) = 2.072(1) x 102 gm(PbO2) = 1 mol x 2.392(1) x 102 g (always 1 mole)m(PbO2) = 2.392(1) x 102 gFrom these, the percentage of the element in question present in the compound can be calculated.m(Pb) x 100%/m(PbO2) = 2.072 g x 100%/2.392 gm(Pb) x 100%/m(PbO2) = 86.62(8)%
How many moles are there in 37 grams of calcium hydroxide?
To find the number of moles in 37 grams of calcium hydroxide, you need to divide the given mass by the molar mass of calcium hydroxide. The molar mass of calcium hydroxide (Ca(OH)2) is 74.1 g/mol. Therefore, 37 grams of calcium hydroxide is equal to 0.499 moles.
How many moles of water are produced if 5.43 mol PbO2 are consumed?
Each mole of PbO2 contains 2 moles of oxygen (O). Thus there would be 5.43x2 = 10.86 moles O.Each mole of water (H2O) contains 1 mole of O, so from 10.86 moles of O you could get 10.86 moles of H2O.
What is the mass ratio of lead per gram of oxygen in the two compounds?
Solve for the masses of oxygen given 1 gram of Pb:For PbO:(1 g Pb)(1 mol Pb/207.2 g Pb)(1 PbO/1 Pb)(1 O/1 PbO)(16 g O/1 mol O) = 0.07722 g OFor PbO2:(1 g Pb)(1 mol Pb/207.2 g Pb)(1 PbO2/1 Pb)(2 O/1 PbO2)(16 g O/1 mol O) = 0.1544 g OFor Pb2O3:(1 g Pb)(1 mol Pb/207.2 g Pb)(1 Pb2O3/2 Pb)(3 O/1 Pb2O3)(16 g O/1 mol O) = 0.1158 g OGet the ratio by dividing the smallest mass of oxygen to the rest of the calculated masses then multiply it by a certain factor to make it a whole number:0.07722 / 0.07722 = 1 x 2 = 20.1544 / 0.07722 = 2 x 2 = 40.1158 / 0.07722 = 1.5 x 2 = 3ANSWER: 2:4:3
What is the mass of 0.7891 mol of ferric oxide (Fe2O3)?
Atomic Mass of Fe: 55.8g/mol Atomic mass of O: 16g/mol Molecular mass of Fe2O3: 2(55.8)+3(16) = 159.6g/mol mass = Molecular mass x number of moles mass = 159.6g/mol x 0.7891mol = 125.94g
What is the mass of 0.50 mol of aluminum foil?
To find the mass of 0.50 mol of aluminum foil, we first need the molar mass of aluminum, which is approximately 27 g/mol. Therefore, the mass can be calculated using the formula: mass = moles × molar mass. For 0.50 mol of aluminum, the mass would be 0.50 mol × 27 g/mol = 13.5 grams.
What is the mass of 0.7891 mol of ferric oxide Fe2O3?
Atomic mass of Fe: 55.8g/mol Atomic mass of O: 16g/mol Molecular mass of Fe2O3: 2(55.8)+3(16) = 159.6g/mol mass = Molecular mass x number of moles mass = 159.6g/mol x 0.7891mol = 125.94g
What is the mass of 0.200 mol of aspirin?
To find the mass of 0.200 mol of aspirin (acetylsalicylic acid), you first need its molar mass. The molar mass of aspirin is approximately 180.16 g/mol. Therefore, the mass of 0.200 mol of aspirin is calculated by multiplying the number of moles by the molar mass: 0.200 mol × 180.16 g/mol = 36.03 g. Thus, the mass of 0.200 mol of aspirin is about 36.03 grams.
What is the mass of 0.7891 mol of ferric oxide?
Atomic Mass of Fe: 55.8g/mol Atomic mass of O: 16g/mol Molecular mass of Fe2O3: 2(55.8)+3(16) = 159.6g/mol mass = Molecular mass x number of moles mass = 159.6g/mol x 0.7891mol = 125.94g
Calculate NaCl in atomic mass?
By adding up the mass numbers of Na (23) and Cl (35 or 37). It is determined by the total of numbers of protons (11 and 17 respectively) and of neutrons (12 and 18 or 20), however it is not a sensible exercition to do, you cannot calculate anything with this figure.
