The product for the reaction between PbO2 and O2 is PbO2.
Cu (copper) reacts with CO2 (carbon dioxide), H2O (water), and O2 (oxygen) to form a product. The specific product formed depends on the reaction conditions and stoichiometry. Without further information, it is not possible to determine the exact reaction and product formed.
The reaction is balanced since 2 moles of PbO2 yield 2 moles of PbO and 1 mole of O2. The law of conservation of mass is upheld with the same number of atoms of each element on both sides of the reaction.
Hydrated Iron (III) oxide: 2Fe + 1.5O2 + xH2O -> Fe2O3·xH2O where x is the number of H2O molecules present.
The product is water:2 H2 + O2 = 2 H2O
2Pb + O2 ----->2PbO then 2PbO + O2 ------> 2PbO2 some mixed oxide will be formed also 2PbO + PbO2 ----->Pb3O4
The balanced chemical equation for the given reaction is: PbO2 + PbO -> 2PbO + O2 Coefficients: 1 PbO2, 1 PbO, 2 PbO, 1 O2.
2PbS + 3O2 ----> 2PbO + 2SO2
PbO2 is an ionic compound composed of lead (Pb) and oxide ions (O2-) bound together by ionic bonds.
Lead + Oxygen -> Lead (IV) Oxide Formula: Pb (s) + O2 (g) -> PbO2 (s)
PbO2 > Pb+O2
To balance the chemical equation Pb + PbO2 + H2SO4 → H2O + PbSO4, start by balancing the Pb atoms on the left side by adding a coefficient of 2 in front of Pb on the left side. Then balance the SO4 atoms by adding a coefficient of 4 in front of H2SO4. The balanced equation is 2Pb + PbO2 + 4H2SO4 → 2H2O + 2PbSO4.
Cu (copper) reacts with CO2 (carbon dioxide), H2O (water), and O2 (oxygen) to form a product. The specific product formed depends on the reaction conditions and stoichiometry. Without further information, it is not possible to determine the exact reaction and product formed.
The reaction is balanced since 2 moles of PbO2 yield 2 moles of PbO and 1 mole of O2. The law of conservation of mass is upheld with the same number of atoms of each element on both sides of the reaction.
When NaOCl (sodium hypochlorite) and PbO2 (lead dioxide) are mixed, a redox reaction occurs where sodium hypochlorite is reduced to chloride ions while lead dioxide is oxidized to lead(IV) chloride. The overall reaction can be represented as: 2NaOCl + PbO2 -> 2NaCl + PbCl4 + O2
Hydrated Iron (III) oxide: 2Fe + 1.5O2 + xH2O -> Fe2O3·xH2O where x is the number of H2O molecules present.
The product in this chemical reaction is nitrogen dioxide (NO2). It is formed by the combination of nitrogen (N) and oxygen (O2) in the presence of a spark or high temperature.
The product is water:2 H2 + O2 = 2 H2O