The balanced chemical equation for the given reaction is: PbO2 + PbO -> 2PbO + O2
Coefficients: 1 PbO2, 1 PbO, 2 PbO, 1 O2.
To balance the chemical equation Pb + PbO2 + H2SO4 → H2O + PbSO4, start by balancing the Pb atoms on the left side by adding a coefficient of 2 in front of Pb on the left side. Then balance the SO4 atoms by adding a coefficient of 4 in front of H2SO4. The balanced equation is 2Pb + PbO2 + 4H2SO4 → 2H2O + 2PbSO4.
Lead Dioxide or Lead IV Oxide
2PbS + 3O2 ----> 2PbO + 2SO2
I believe that there is a typo in the formula, because of the ionization state of the lead. In the reactant PbO2, each oxygen carries a -2 charge, so the Pb must be +4, but in the products, PbSO4 is the problem... The SO4 will carry a -2 charge, which means the lead must now be a +2, If the lead went from +4 to +2, it would have had to get 2 electrons from somewhere.... So, the equation is balanced if it is: PbO2 + 2H2SO4 ---> Pb(SO4)2 + 2H2O or: PbO + H2SO4 ---> PbSO4 + H2O
PbO2 > Pb+O2
To balance the chemical equation Pb + PbO2 + H2SO4 → H2O + PbSO4, start by balancing the Pb atoms on the left side by adding a coefficient of 2 in front of Pb on the left side. Then balance the SO4 atoms by adding a coefficient of 4 in front of H2SO4. The balanced equation is 2Pb + PbO2 + 4H2SO4 → 2H2O + 2PbSO4.
Lead Dioxide or Lead IV Oxide
Formula: PbO2
PbO2
2PbS + 3O2 ----> 2PbO + 2SO2
2Pb + O2 ----->2PbO then 2PbO + O2 ------> 2PbO2 some mixed oxide will be formed also 2PbO + PbO2 ----->Pb3O4
I believe that there is a typo in the formula, because of the ionization state of the lead. In the reactant PbO2, each oxygen carries a -2 charge, so the Pb must be +4, but in the products, PbSO4 is the problem... The SO4 will carry a -2 charge, which means the lead must now be a +2, If the lead went from +4 to +2, it would have had to get 2 electrons from somewhere.... So, the equation is balanced if it is: PbO2 + 2H2SO4 ---> Pb(SO4)2 + 2H2O or: PbO + H2SO4 ---> PbSO4 + H2O
The chemical formula for lead(II) oxide is PbO.
PbO2 > Pb+O2
When lead dioxide reacts with sulfuric acid, it forms lead sulfate and water. The balanced chemical equation for this reaction is: PbO2 + H2SO4 -> PbSO4 + H2O
the positive plate is Pb the negative is PbO2 and the acid is H2SO4.
The product for the reaction between PbO2 and O2 is PbO2.