If it's pure water, 250mL of water will have a mass of 250g. 250g / 18gmol-1 = approx. 14mol.
95,474 moles
27.4 g H2O x 1 mole/18 g = 1.52 moles
Only when 5.5 mole O2 react with 11 mole H2, then 11 mole H2O are formed.
The balanced chemical equation for the reaction between ammonia (NH3) and water (H2O) is: 4NH3 + 5O2 → 4NO + 6H2O. This means that for every 4 moles of ammonia, 6 moles of water are produced. Therefore, if 2 moles of ammonia are used, 3 moles of water vapor can be produced.
To find the number of moles in 0.34g of water, you first need to calculate the molar mass of water, which is approximately 18g/mol. Then, divide the given mass by the molar mass to get the number of moles. Therefore, 0.34g / 18g/mol ≈ 0.019 moles of water.
There are 84.54 US fluid ounces in 2500ml. :)
The answer is 6 moles.
9.991 Moles (water) 8.982 Moles (heavy water)
95,474 moles
2500ml
2500ml
There are 2500 cubic centimeters (cc) in 2500 ml, as 1 ml is equivalent to 1 cc.
180 grams of water is 10 moles of water.
3.2 moles of water (H2O)
The answer is 3 moles.
54,0 grams of water is equivalent to 3 moles.
To find the molarity of the solution, first calculate the number of moles of lithium sulfate in 734g. Then, divide the moles by the volume of solution in liters to get the molarity. Remember to convert grams to moles using the molar mass of lithium sulfate (Li2SO4).