To determine the molar mass of propane (C3H8), add the atomic masses of all the atoms present:
3C = 3x12 = 36
8H = 8x1 = 8
Total = 36 + 8 = 44 g/mole = molar mass of propane
To find the number of moles of propane in the container, first convert the mass of propane to grams: 2.55 kg = 2550 grams Next, calculate the number of moles using the molar mass of propane: Molar mass of C3H8 = 44.11 g/mol Number of moles = 2550 g / 44.11 g/mol = 57.86 moles Therefore, there are 57.86 moles of propane in the pressure container.
This question sound like one that can easily be answered if one has a general chemistry textbook. My advice is to look at doing some unit conversions to find out how many moles of propane are in 36.1 g of propane first. With a balanced chemical equation for combustion, and assuming the propane is the limiting reagent, use dimensional analysis to convert your moles of propane to moles of carbon dioxide.
Calculate the mass in grams of water vapor produced if 3.11 moles of propane is burned
To find the number of moles in 171 g of CF4, you first need to calculate the molar mass of CF4. Carbon has a molar mass of 12.01 g/mol and each fluorine atom has a molar mass of 19.00 g/mol, giving a total molar mass of CF4 as 88.01 g/mol. Then divide 171 g by the molar mass of CF4 to get the number of moles.
27.4 g H2O x 1 mole/18 g = 1.52 moles
To find the number of moles of propane in the container, first convert the mass of propane to grams: 2.55 kg = 2550 grams Next, calculate the number of moles using the molar mass of propane: Molar mass of C3H8 = 44.11 g/mol Number of moles = 2550 g / 44.11 g/mol = 57.86 moles Therefore, there are 57.86 moles of propane in the pressure container.
To find the total number of moles in 0.44 g of propane (C₃H₈), you first need to calculate its molar mass. The molar mass of propane is approximately 44.1 g/mol. Using the formula ( \text{moles} = \frac{\text{mass}}{\text{molar mass}} ), you can calculate the moles: ( \frac{0.44 , \text{g}}{44.1 , \text{g/mol}} \approx 0.01 ) moles of propane.
5.8
This question sound like one that can easily be answered if one has a general chemistry textbook. My advice is to look at doing some unit conversions to find out how many moles of propane are in 36.1 g of propane first. With a balanced chemical equation for combustion, and assuming the propane is the limiting reagent, use dimensional analysis to convert your moles of propane to moles of carbon dioxide.
Calculate the mass in grams of water vapor produced if 3.11 moles of propane is burned
The formula is: number of moles = g Be/9,012.
Molar mass of propane = 44 g/mole ... 100 / 44 = 2.727 moles one mole occupies 22.4 L at STP .... 22.4 x 2.727 = 50.91 L
To find the number of moles in 171 g of CF4, you first need to calculate the molar mass of CF4. Carbon has a molar mass of 12.01 g/mol and each fluorine atom has a molar mass of 19.00 g/mol, giving a total molar mass of CF4 as 88.01 g/mol. Then divide 171 g by the molar mass of CF4 to get the number of moles.
14,84 g magnesium are equivalent to 0,61 moles.
97,5 g of oxygen is equal to 5,416 moles.
978 g calcium contain 24,4 moles.
573,28 of g of AgCI is equivalent to 4 moles.