Molar mass of propane = 44 g/mole
... 100 / 44 = 2.727 moles
one mole occupies 22.4 L at STP
.... 22.4 x 2.727 = 50.91 L
At standard temperature and pressure (STP), 1 mole of any gas occupies 22.4 liters. Therefore, a volume of 22.4 liters will be occupied by 1 mole of Cl2 gas at STP.
To find the volume occupied by 20.4 liters of CO2 at STP (Standard Temperature and Pressure, defined as 0°C and 1 atm), we can use the ideal gas law and the concept of proportionality. At STP, 1 mole of gas occupies 22.4 liters, and 1200 torr is approximately 1.58 atm. Using the combined gas law, we can calculate the volume at STP: [ V_{STP} = V_{initial} \times \frac{P_{initial}}{P_{STP}} \times \frac{T_{STP}}{T_{initial}} ] Substituting the known values, the volume at STP will be approximately 12.9 liters.
At standard temperature and pressure (STP), one mole of an ideal gas occupies 22.4 liters. Therefore, to find the volume occupied by 0.685 mol of gas at STP, you can multiply the number of moles by the volume per mole: 0.685 mol × 22.4 L/mol = 15.34 liters. Thus, 0.685 mol of gas occupies approximately 15.34 liters at STP.
The van der Waals equation of state is not typically used for calculating the volume of gases at STP (Standard Temperature and Pressure). Instead, you can use the ideal gas law, which states that at STP, 1 mole of gas occupies 22.4 L. Since ammonia (NH3) has a molar mass of 17.03 g/mol, 7.40 g of NH3 is approximately 0.435 moles. Therefore, the volume occupied by 7.40 g of NH3 at STP is around 9.74 L.
The volume of a gas depends on its pressure, temperature, and volume according to the ideal gas law PV = nRT. Without knowing the pressure, temperature, or container size, it's not possible to determine the volume occupied by the 0.48 moles of hydrogen.
At STP (standard temperature and pressure: 0 degrees Celsius and 1 atm), the volume taken up by 132 grams of propane can be calculated using the ideal gas law. First, find the number of moles of propane using its molar mass, and then use the ideal gas law equation to calculate the volume, which will be around 66.6 L.
1 mole of any gas at STP occupies 22.4 liters. Thus, 2 moles propane will occupy 2 x 22.4 L = 44.8 liters.
At standard temperature and pressure (STP), 1 mole of any gas occupies 22.4 liters. Therefore, a volume of 22.4 liters will be occupied by 1 mole of Cl2 gas at STP.
The molar volume of a gas at STP (standard temperature and pressure) is 22.4 L/mol. Therefore, the volume occupied by 2 moles of oxygen would be 44.8 L.
At standard temperature and pressure (STP), the volume occupied by 1 mole of any ideal gas is 22.4 liters. Therefore, the volume of 1.42 moles of ammonia at STP would be 1.42 * 22.4 liters = 31.808 liters.
The volume occupied by 0.25 mol of any ideal gas at standard temperature and pressure (STP) is approximately 5.6 L. This is based on the molar volume of an ideal gas at STP, which is around 22.4 L/mol.
To find the volume occupied by 20.4 liters of CO2 at STP (Standard Temperature and Pressure, defined as 0°C and 1 atm), we can use the ideal gas law and the concept of proportionality. At STP, 1 mole of gas occupies 22.4 liters, and 1200 torr is approximately 1.58 atm. Using the combined gas law, we can calculate the volume at STP: [ V_{STP} = V_{initial} \times \frac{P_{initial}}{P_{STP}} \times \frac{T_{STP}}{T_{initial}} ] Substituting the known values, the volume at STP will be approximately 12.9 liters.
The volume of CO2 is 4,94 L.
To find the volume of propane at STP (standard temperature and pressure), we need to use the ideal gas law equation: PV = nRT, where P is pressure, V is volume, n is the number of moles, R is the ideal gas constant, and T is temperature. First, calculate the number of moles of propane using the given conditions. Then, use this information and the conditions at STP (273 K and 1 atm) to find the new volume. Remember to convert 922 torr to atm for the calculations.
The amount of oxygen is 0,067 moles.
At standard temperature and pressure (STP), one mole of an ideal gas occupies 22.4 liters. Therefore, to find the volume occupied by 0.685 mol of gas at STP, you can multiply the number of moles by the volume per mole: 0.685 mol × 22.4 L/mol = 15.34 liters. Thus, 0.685 mol of gas occupies approximately 15.34 liters at STP.
At STP conditions (standard temperature and pressure), the volume occupied by 1 mole of ideal gas is 22.4 liters. Since the molar mass of SO2 is approximately 64 g/mol, 11 g of SO2 is about 0.172 moles. Therefore, the volume of 11 g of SO2 at STP would be approximately 3.85 liters.