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7.996*1023 Let's see if I can remember how to do this.

I think the Atomic Mass of Argon is about 39.9 approx, so 1 mole of Argon weighs 39.9grammes.

Avogadro's number tells us how many atoms are in 1 mole of any element. The value is about 6.0221415 x 10^23.

So in 39.9grammes we have 6.0221415 x 10^23 atoms (because as far as I remember Argon is a monatomic gas - i.e. unlike for example Oxygen which hangs around in pairs of Oxygen atoms O2)

Anyway, number of atoms/particles in 23.9g of Argon would be about (23.9/39.9) x 6.0221415 x 10^23 = 3.607 x 10^23 particles.

That looks about right........................... Unless of course you meant to include sub-atomic particles................ That's too hard.

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