7.996*1023 Let's see if I can remember how to do this.
I think the Atomic Mass of Argon is about 39.9 approx, so 1 mole of Argon weighs 39.9grammes.
Avogadro's number tells us how many atoms are in 1 mole of any element. The value is about 6.0221415 x 10^23.
So in 39.9grammes we have 6.0221415 x 10^23 atoms (because as far as I remember Argon is a monatomic gas - i.e. unlike for example Oxygen which hangs around in pairs of Oxygen atoms O2)
Anyway, number of atoms/particles in 23.9g of Argon would be about (23.9/39.9) x 6.0221415 x 10^23 = 3.607 x 10^23 particles.
That looks about right........................... Unless of course you meant to include sub-atomic particles................ That's too hard.
Who asked this anyway?
One mole of argon has 6,022 140 857(74) atoms.
There are approx 1.19*10^24 atoms.
moles = mass in grams / atomic weight So moles in 37.9 g or argon = 37.9 / 39.948 = 0.948 moles
Argon has an atomic mass of 39.948. Therefore, it has 39.948 grams per mol. Ar(mol) = 14.5 g / 39.948 g/mol Ar(mol) = 0.363 mol
The mass number of Argon is 39.948 so it is 119.98/39.948=3.0034 moles of Argon in 119.98 g of Argon or approximately 3 moles of Argon is in 119.98 g this gas.
Moles = weight in g / atomic weight. So moles in 24.7 g of Ar = 24.7 / 39.948 = 0.62 moles
2.3 × 1024 atoms of Ar
Cl2 has a molar mass of about 71 g/moleArgon has molar mass of about 40 g/mole Thus, Argon will diffuse faster than Cl2 gas, or put another way, Cl2 will diffuse slower than argon.
Cl2 has a molar mass of about 71 g/moleArgon has molar mass of about 40 g/mole Thus, Argon will diffuse faster than Cl2 gas, or put another way, Cl2 will diffuse slower than argon.
moles = mass in grams / atomic weight So moles in 37.9 g or argon = 37.9 / 39.948 = 0.948 moles
2.3 × 1024 atoms of Ar
Argon has an atomic mass of 39.948. Therefore, it has 39.948 grams per mol. Ar(mol) = 14.5 g / 39.948 g/mol Ar(mol) = 0.363 mol
The mass number of Argon is 39.948 so it is 119.98/39.948=3.0034 moles of Argon in 119.98 g of Argon or approximately 3 moles of Argon is in 119.98 g this gas.
Moles = weight in g / atomic weight. So moles in 24.7 g of Ar = 24.7 / 39.948 = 0.62 moles
2.3 × 1024 atoms of Ar
Have: 607gAr Need: Moles of Argon From the periodic table we know that there are 39.948gAr per every 1 mole of Argon. 607g/39.948 = your answer.
just divide the mass of sample by the mass of argon. OR: atomic mass of argon is 40 g/mol, so in a 40g sample of argon, there ought to be 1 mole atoms, or 6.02x10^23 atoms
Plutonium-239, the most important isotope, emit alpha particles, gamma and X-rays. The specific activity is 0,062 Ci/g.
For plutonium 239: ca. 74,68.1023 atoms