How much of a 2 mole NaOH solution would be required to neutralize 20mL of a 6 mole HCl solution?

Answer 1

I assume you mean molar instead of mole?

Fast:

The HCl solution is 3 times as concentrated.

Since both can only donate 1 H+ or OH-...

you wil need 3 times as much NaOH to neutralise the HCl.

20 ml * 3 = 60 ml

Slow:

The HCl solution has 6 mol/L

There is 20 ml of it, so you have 0.02 L * 6 mol/L = 0.12 mol of HCl

Each mole of HCl donates 1 mole of H+

So there is 0.12 mol of H+ that you have to neutralise.

This equals to 0.12 mol OH-

Each NaOH donates 1 OH-

So you need 0.12 mol NaOH

The NaOH solution you are using has 2 mol/L

So you have to use 0.12 mol / 2 mol/L = 0.06 L = 60 ml

Answer 2

To neutralize the HCl solution, you would need an equal number of moles of NaOH. Since the mole ratio of HCl to NaOH is 1:1, you would need 2 moles of NaOH. This would require 40mL of the 2 mole NaOH solution to neutralize the 20mL of 6 mole HCl solution.