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To prepare a 0.02 M (molar) solution of H2SO4 (sulfuric acid), you would first need to calculate the amount of sulfuric acid needed based on its molar mass (98.08 g/mol). Then, measure out the calculated mass of H2SO4 using a balance and dissolve it in a known volume of water to make the desired concentration. For example, to make 1 liter of 0.02 M H2SO4, you would dissolve 19.62 grams of H2SO4 in enough water to make 1 liter of solution.
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What volume of 6.40 m h2so4 is needed to prepare 455.0ml of a solution that is 0.700m in h2so4?
To find the volume of 6.40 M H2SO4 needed to prepare a solution that is 0.700 M, you can use the formula: M1V1 = M2V2, where M1 is the initial concentration, V1 is the initial volume, M2 is the final concentration, and V2 is the final volume. Rearranging the formula, V1 = (M2*V2) / M1 gives you the volume: V1 = (0.700 * 455.0) / 6.40 = 49.53 ml. You would need 49.53 ml of the 6.40 M H2SO4 solution to prepare 455.0 ml of a 0.700 M H2SO4 solution.
How do you prepare 2.5N h2so4?
how 2.5N H2SO4 prepared from concentrated H2SO4
What volume of 8.0 M H2SO4 is required to prepare 200.0 ml of a 0.50 M?
To prepare a 200ml solution of 0.5M H2SO4, you need to add 12.5ml of 8M H2SO4 and then dilute it up to 200ml. Well, this is how to calculate it, I'll go straight to the equation. use the M1V1 = M2V2 equation, M1 = 8.0 M V1 = Volume needed M2 = 0.5 M V2 = 200 ml 8.0 M x V1 = 0.5 M x 200 ml V1 = (0.5 M x 200 ml)/ 8.0 M = 12.5 ml Cheers :)
What volume of 18.0 m sulfuric acid is required to prepare 19.6 L of 0.126 m H2SO4?
Using V * M = constant at dilution = amount of H2SO4 [mol] in both of the solutionsV= volume [L] of the solutionM= molarity [mol/L] of the solutionSo: V *18.0 = 24.9 * 0.195 gives V = ( 24.9 * 0.195 ) / 18.0 = 0.270 L
How will you make solution for ph4 of 0.005 normal h2so4?
To prepare a 0.005 M solution of H2SO4 with pH 4, you can first calculate the concentration of H+ ions needed to achieve a pH of 4. Then, use the dissociation of H2SO4 to determine the amount of H2SO4 needed to provide that concentration of H+ ions. Finally, dilute the calculated amount of H2SO4 with water to reach the desired volume of the solution.
What volume of 6.40 m h2so4 is needed to prepare 455.0ml of a solution that is 0.700m in h2so4?
To find the volume of 6.40 M H2SO4 needed to prepare a solution that is 0.700 M, you can use the formula: M1V1 = M2V2, where M1 is the initial concentration, V1 is the initial volume, M2 is the final concentration, and V2 is the final volume. Rearranging the formula, V1 = (M2*V2) / M1 gives you the volume: V1 = (0.700 * 455.0) / 6.40 = 49.53 ml. You would need 49.53 ml of the 6.40 M H2SO4 solution to prepare 455.0 ml of a 0.700 M H2SO4 solution.
How do you prepare 2.5N h2so4?
how 2.5N H2SO4 prepared from concentrated H2SO4
What volume of 8.0 M H2SO4 is required to prepare 200.0 ml of a 0.50 M?
To prepare a 200ml solution of 0.5M H2SO4, you need to add 12.5ml of 8M H2SO4 and then dilute it up to 200ml. Well, this is how to calculate it, I'll go straight to the equation. use the M1V1 = M2V2 equation, M1 = 8.0 M V1 = Volume needed M2 = 0.5 M V2 = 200 ml 8.0 M x V1 = 0.5 M x 200 ml V1 = (0.5 M x 200 ml)/ 8.0 M = 12.5 ml Cheers :)
What volume of 18.0 m sulfuric acid is required to prepare 19.6 L of 0.126 m H2SO4?
Using V * M = constant at dilution = amount of H2SO4 [mol] in both of the solutionsV= volume [L] of the solutionM= molarity [mol/L] of the solutionSo: V *18.0 = 24.9 * 0.195 gives V = ( 24.9 * 0.195 ) / 18.0 = 0.270 L
How will you make solution for ph4 of 0.005 normal h2so4?
To prepare a 0.005 M solution of H2SO4 with pH 4, you can first calculate the concentration of H+ ions needed to achieve a pH of 4. Then, use the dissociation of H2SO4 to determine the amount of H2SO4 needed to provide that concentration of H+ ions. Finally, dilute the calculated amount of H2SO4 with water to reach the desired volume of the solution.
How can you prepare 1N H2SO4 from H2SO4 95 percent?
To prepare 1N H2SO4 from 95% H2SO4, you would first need to dilute the 95% H2SO4 with water by adding the appropriate amount of water to achieve the desired concentration. To calculate the volume of 95% H2SO4 needed to make 1N solution, you need to use the formula: (Normality of stock solution) * (Volume of stock solution) = (Normality of diluted solution) * (Volume of diluted solution). Adjust the volumes accordingly to prepare the desired 1N solution.
How much H2SO4 is needed to prepare 2000ml of 1.25H2SO4 from 98 ww H2SO4?
You need 252 g sulfuric acid.
How do you prepare the 1.25 H2SO4 from 98 ww H2SO4?
Mix 120 g sulfuric acid with water to 1000 mL.
What is the total number of moles of H2SO4 needed to prepare 5.0 liters of a 2.0 M solution of H2SO4?
To find the total number of moles needed, use the formula n = M x V, where n is the number of moles, M is the molarity, and V is the volume in liters. Thus, n = 2.0 mol/L x 5.0 L = 10 moles of H2SO4 are needed.
How can you prepare H2SO4 0.25N?
To prepare a 0.25N solution of H2SO4, you would need to dilute concentrated sulfuric acid (typically around 95-98% purity) with water. For example, to prepare 1L of 0.25N H2SO4, you would mix 20.6mL of concentrated H2SO4 with approximately 980mL of water. Always add acid to water slowly and carefully while stirring to avoid splashing and heat generation.
What volume of 0.744 Molarity of NaOH is required to titrate 10.00ml of 0.526 M H2SO4?
The balanced chemical equation for the reaction between NaOH and H2SO4 is 2NaOH + H2SO4 ⟶ Na2SO4 + 2H2O. From the equation, it is a 1:1 ratio of NaOH to H2SO4. Therefore, to neutralize 10.00 ml of 0.526 M H2SO4, you will need the same amount of 0.526 M NaOH, which is 10.00 ml.
How do you dilute a 10 M H2SO4 to 1M H2SO4?
Remember M1V1=M2V2, where M is molarity and V is volume. M1/M2=V2/V1, 10/1=v2/v1, For diluting the acid, we can add acid to water. So, assuming that 10M H2SO4 is having 1ml of water, we should add 1M of H2So4 to 10ml of water.
