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C5H8 + 7O2 5CO2 + 4H2O
The balanced equation for the combustion reaction C5H8 + 5 O2 → 5 CO2 + 4 H2O.
C5h8 + 7o2 --> 5co2 + 4h2o
The balanced equation for the complete combustion of ethyne (C2H2) is: 2C2H2 + 5O2 -> 4CO2 + 2H2O
The reaction between Cl2 and hexene would yield several products depending on the conditions, but a possible equation could be: Cl2 + C6H12 → C6H11Cl + HCl
The reaction between C5H10Br2 and NaNH2 in liquid ammonia results in the formation of a diene compound known as 1,5-hexadiene. The NaNH2 acts as a strong base and abstracts a proton from the dihalide compound, leading to the formation of the diene product.
The balanced equation for the combustion reaction C5H8 + 5 O2 → 5 CO2 + 4 H2O.
C5h8 + 7o2 --> 5co2 + 4h2o
The reaction C5H8 + 7O2 → 5CO2 + 4H2O is an example of a combustion reaction. In this process, the hydrocarbon (C5H8) reacts with oxygen (O2) to produce carbon dioxide (CO2) and water (H2O), releasing energy in the form of heat and light. Combustion reactions are typically characterized by the burning of a fuel in the presence of an oxidizer.
The balanced equation for the complete combustion of ethyne (C2H2) is: 2C2H2 + 5O2 -> 4CO2 + 2H2O
The reaction of C5H8(g) with O2(g) produces CO2(g) and H2O(g) while releasing 3536 kJ of energy, indicating it is an exothermic combustion reaction. Specifically, the balanced equation is: [ \text{C}_5\text{H}_8(g) + 8 \text{O}_2(g) \rightarrow 5 \text{CO}_2(g) + 6 \text{H}_2\text{O}(g) + 3536 \text{ kJ} ] This shows that for every mole of C5H8 combusted, a significant amount of energy is released, demonstrating the efficiency of hydrocarbons as fuel sources.
The reaction between Cl2 and hexene would yield several products depending on the conditions, but a possible equation could be: Cl2 + C6H12 → C6H11Cl + HCl
Formula: (C5H8)n
pentyne
In the given reaction, ( \text{C}5\text{H}{12} ) is converted to ( \text{C}_5\text{H}_8 ) with the production of ( 2 , \text{H}_2 ). The balanced equation shows that 1 mole of ( \text{C}5\text{H}{12} ) produces 2 moles of ( \text{H}_2 ). Therefore, the mole ratio of ( \text{C}5\text{H}{12} ) to ( \text{H}_2 ) is 1:2.
The reaction between C5H10Br2 and NaNH2 in liquid ammonia results in the formation of a diene compound known as 1,5-hexadiene. The NaNH2 acts as a strong base and abstracts a proton from the dihalide compound, leading to the formation of the diene product.
The molecule is cyclopentene with molecular formula C5H8. So there are 8 hydrogen atoms.
Sure.Erasers are made of rubber.Natural rubber is a polymer of Isoprene, which is an organic compound with the formula C5H8. Theoretically, since erasers are made of something that is a compound, then they should be considered a compound.