The reaction of C5H8(g) with O2(g) produces CO2(g) and H2O(g) while releasing 3536 kJ of energy, indicating it is an exothermic combustion reaction. Specifically, the balanced equation is: [ \text{C}_5\text{H}_8(g) + 8 \text{O}_2(g) \rightarrow 5 \text{CO}_2(g) + 6 \text{H}_2\text{O}(g) + 3536 \text{ kJ} ] This shows that for every mole of C5H8 combusted, a significant amount of energy is released, demonstrating the efficiency of hydrocarbons as fuel sources.
In the given reaction, ( \text{C}5\text{H}{12} ) is converted to ( \text{C}_5\text{H}_8 ) with the production of ( 2 , \text{H}_2 ). The balanced equation shows that 1 mole of ( \text{C}5\text{H}{12} ) produces 2 moles of ( \text{H}_2 ). Therefore, the mole ratio of ( \text{C}5\text{H}{12} ) to ( \text{H}_2 ) is 1:2.
The equation, including the catalyst for the hydration of 1-methylcyclobutene is: C5H8 + H2O + HX ---> C5H8OH + H2O.
Pentyne is an alkyne with five carbon atoms in its longest carbon chain. The molecular formula for pentyne is C5H8, indicating that it contains five carbon atoms. There are two isomers of pentyne: 1-pentyne and 2-pentyne, both of which have the same number of carbon atoms.
The monomer unit of rubber is isoprene, a hydrocarbon with the chemical formula C5H8. Isoprene can polymerize to form polyisoprene, which is the primary component of natural rubber. This polymer structure gives rubber its unique elastic properties, allowing it to stretch and return to its original shape. Synthetic rubbers can also be derived from various monomers, but isoprene remains the fundamental building block for natural rubber.
The balanced equation for the combustion reaction C5H8 + 5 O2 → 5 CO2 + 4 H2O.
Answer this question… C5H8 + 7O2 5CO2 + 4H2O
C5h8 + 7o2 --> 5co2 + 4h2o
The balanced equation for the complete combustion of ethyne (C2H2) is: 2C2H2 + 5O2 -> 4CO2 + 2H2O
The reaction of C5H8(g) with O2(g) produces CO2(g) and H2O(g) while releasing 3536 kJ of energy, indicating it is an exothermic combustion reaction. Specifically, the balanced equation is: [ \text{C}_5\text{H}_8(g) + 8 \text{O}_2(g) \rightarrow 5 \text{CO}_2(g) + 6 \text{H}_2\text{O}(g) + 3536 \text{ kJ} ] This shows that for every mole of C5H8 combusted, a significant amount of energy is released, demonstrating the efficiency of hydrocarbons as fuel sources.
The reaction between Cl2 and hexene would yield several products depending on the conditions, but a possible equation could be: Cl2 + C6H12 → C6H11Cl + HCl
Formula: (C5H8)n
pentyne
The reaction between C5H10Br2 and NaNH2 in liquid ammonia results in the formation of a diene compound known as 1,5-hexadiene. The NaNH2 acts as a strong base and abstracts a proton from the dihalide compound, leading to the formation of the diene product.
The molecule is cyclopentene with molecular formula C5H8. So there are 8 hydrogen atoms.
In the given reaction, ( \text{C}5\text{H}{12} ) is converted to ( \text{C}_5\text{H}_8 ) with the production of ( 2 , \text{H}_2 ). The balanced equation shows that 1 mole of ( \text{C}5\text{H}{12} ) produces 2 moles of ( \text{H}_2 ). Therefore, the mole ratio of ( \text{C}5\text{H}{12} ) to ( \text{H}_2 ) is 1:2.
The equation, including the catalyst for the hydration of 1-methylcyclobutene is: C5H8 + H2O + HX ---> C5H8OH + H2O.