Theoretically: dissolve 571,59 g of zinc uranyl acetate in 1 L water.
But zinc uranyl acetate is not so soluble.
I recommend a concentration of max. o,1 M (57,159 g of zinc uranyl acetate in 1 L water).
the molar mass of cortisone acetate is about 403.2 g/mol.
The molar mass of methyl acetate (CH3COOCH3) is 74.08 g/mol.
The molar mass of ethyl acetate is approximately 88.11 g/mol.
The molar mass of aluminum acetate (Al(C2H3O2)3) is approximately 204.11 g/mol.
To prepare a 0.1 N solution of K2Cr2O7, you need to calculate the molar mass of K2Cr2O7 and use the formula for normality. By dividing the given weight by the molar mass, you can determine the number of moles present, and then calculate the normality using the volume of the solution.
You have to dissolve 1.00 mol, that is 98.15 g CH3COOK (its molar mass being 98.15 g/mol), in upto 1.000 L.(Suggested procedure: dissolve 98.15 g CH3COOK in not more then 900 mL, homogenize and fill up to exactly 1.000 L by carefully adding the last millilitres water).
the molar mass of cortisone acetate is about 403.2 g/mol.
The chemical formula of aluminium acetate is Al(CH3COO)3 and the molar mass is 161,9745 g.The concentration of your solution is 50,6 g/L.
The molar mass of calcium acetate is approximately 142 g/mol.
The molar mass of methyl acetate (CH3COOCH3) is 74.08 g/mol.
The molar mass of ethyl acetate is approximately 88.11 g/mol.
The molar mass of aluminum acetate (Al(C2H3O2)3) is approximately 204.11 g/mol.
The pH of a 0.01M solution of sodium acetate would be around 8.9. This is because sodium acetate is a salt of a weak acid (acetic acid) and a strong base (sodium hydroxide), so it produces a basic solution. The acetate ions react with water to form hydroxide ions, increasing the pH.
Dissolve 294,185 g of potassium dichromate in 1L demineralized water.
To prepare a 0.1 N solution of K2Cr2O7, you need to calculate the molar mass of K2Cr2O7 and use the formula for normality. By dividing the given weight by the molar mass, you can determine the number of moles present, and then calculate the normality using the volume of the solution.
82.03 g/mol (anhydrous)=136.08 g/mol (trihydrate)=
Molarity = moles solute/liters solution = 0.207 moles/0.1665 L = 1.24 molar (3 sig. figs.)