Add 200 mL concentrated (12 M) hydrochloric acid to 200 mL distilled water while stirring. CAUTION: Never add water to acid.
To prepare 6N HCl from 1N HCl, you can dilute the 1N HCl by adding 6 times the volume of water to the 1N HCl solution. For example, mix 1 volume of 1N HCl with 6 volumes of water to get a final concentration of 6N HCl. Make sure to add acid to water slowly with stirring to avoid splashes and heat generation.
6N HCl refers to a 6 molar solution of hydrochloric acid. The strength of the acid solution is determined by its concentration. It is a moderately strong acid that can cause skin irritation and burns upon contact.
To prepare 2 liters of 5.5 molar HCl solution, you would need to dissolve 217.5 grams of hydrochloric acid (HCl) in enough water to make 2 liters of solution. Make sure to wear appropriate safety gear and handle the acid with care, as it is corrosive. Start by measuring the appropriate amount of acid and then slowly add it to the water while stirring until fully dissolved.
To prepare several different pH solutions from a 1 Molar stock solution of HCl, you can dilute the stock solution with water to achieve the desired pH. You can use a pH meter to measure and adjust the pH as needed by adding either more stock solution or more water. Make sure to handle HCl with caution as it is a strong acid.
To prepare 600 mL of 1 M HCl solution from a 6 M stock solution, you can use the formula: M1V1 = M2V2, where M1 = concentration of stock solution, V1 = volume of stock solution needed, M2 = final concentration, and V2 = final volume. Plugging in the values: 6 M x V1 = 1 M x 600 mL. Therefore, V1 = 100 mL. Therefore, you would need to measure 100 mL of the 6 M stock solution and dilute it to 600 mL with water to make a 1 M HCl solution.
To prepare 6N HCl from 1N HCl, you can dilute the 1N HCl by adding 6 times the volume of water to the 1N HCl solution. For example, mix 1 volume of 1N HCl with 6 volumes of water to get a final concentration of 6N HCl. Make sure to add acid to water slowly with stirring to avoid splashes and heat generation.
6N HCl refers to a 6 molar solution of hydrochloric acid. The strength of the acid solution is determined by its concentration. It is a moderately strong acid that can cause skin irritation and burns upon contact.
To prepare 2 liters of 5.5 molar HCl solution, you would need to dissolve 217.5 grams of hydrochloric acid (HCl) in enough water to make 2 liters of solution. Make sure to wear appropriate safety gear and handle the acid with care, as it is corrosive. Start by measuring the appropriate amount of acid and then slowly add it to the water while stirring until fully dissolved.
To prepare several different pH solutions from a 1 Molar stock solution of HCl, you can dilute the stock solution with water to achieve the desired pH. You can use a pH meter to measure and adjust the pH as needed by adding either more stock solution or more water. Make sure to handle HCl with caution as it is a strong acid.
To prepare 600 mL of 1 M HCl solution from a 6 M stock solution, you can use the formula: M1V1 = M2V2, where M1 = concentration of stock solution, V1 = volume of stock solution needed, M2 = final concentration, and V2 = final volume. Plugging in the values: 6 M x V1 = 1 M x 600 mL. Therefore, V1 = 100 mL. Therefore, you would need to measure 100 mL of the 6 M stock solution and dilute it to 600 mL with water to make a 1 M HCl solution.
To find the number of moles in 2 grams of HCl, you need to divide the mass by the molar mass of HCl. The molar mass of HCl is approximately 36.46 g/mol. Therefore, 2 grams of HCl is equal to 2/36.46 = 0.055 moles.
Concentrated HCl is typically 36.5% industrially. It is thus almost exactly 10 Molar.
I'm not certain what is meant by 38 HCl, but I suspect it must mean 38% HCl. Typically, concentrated Hydrochloric Acid is about 36-38%. 38% W/W means each 100 grams of 38% HCl contains 38 grams of dissolved hydrogen chloride gas. Generally, concentrated HCl is considered to by 12 Formal (or less correctly, 12 Molar) which is equivalent to 12 Normal. A close approximation of 0.5M would be as follows, using a Volume/Volume prep: Combine 11.5 parts water and add 0.5 parts 12 Molar HCl. For example: 115 mL of water plus 5 mL of 12 M HCl.
To find the number of moles in 108 grams of HCl, you need to know the molar mass of HCl, which is about 36.5 g/mol. You can then use this molar mass to calculate the number of moles by dividing the given mass by the molar mass. In this case, 108 grams divided by 36.5 g/mol gives you about 2.96 moles of HCl.
8.3 grams HCl (1 mole HCl/36.458 grams) = 0.23 moles HCl ------------------------
1N HCL is the same as 1 Molar HCl. You take the # of H ions and multiply by the molarity to get the Normality. Usually you buy HCl in concentrated form which is 12 Molar or 12 Normal HCL. You need to dilute the concentrated HCl to get the reduced concentration. Use the formula Molarity Initial x Volume Initial = Molarity Final x Volume Final ex. 12 M HCL x 10 ml = 1 M x 120 ml. So take 10 ml of concentrated HCl and add enough water to make 120 ml. This will give you 120 ml of 1 M (which is 1N) HCl. Venkat Reddy
To create a two molar solution of HCl, you would need to dissolve 73.0 grams of hydrochloric acid (HCl) in enough water to make 1 liter of solution. This would give you a 2 molar (2M) solution of HCl. Be sure to wear appropriate safety gear and handle the acid with caution.