The freezing point of water would decrease if 4 mol of NaCl were added because NaCl is a solute that disrupts the water molecules' ability to form solid ice. Each mole of NaCl added to water reduces the freezing point by approximately 1.86 degrees Celsius. So, with 4 mol of NaCl added, the freezing point of water would decrease by about 7.44 degrees Celsius.
The freezing point of water decreases by about 1.86 degrees Celsius for each mole of solute (such as sugar) dissolved in 1 kg of water. So, the freezing point would decrease by 1.86 degrees Celsius for every mole of sugar added.
The melting point of ice decreases when salt is added.
The freezing point depression constant for water is 1.86°C kg/mol. With 4 moles of NaCl added to 1 kg of water, the molality would be 4 mol / 1 kg = 4 m. The freezing point depression can be calculated as 1.86°C kg/mol * 4 m = 7.44°C.
it lowers it. impurities lower the melting and raise the boiling point of substances. they also cause the melting point to fall over a range now. for example, water's melting point was initially 0 but upon adding salt it now is -5 to -1 degrees celsius.
The freezing point of a solution decreases according to the formula: delta Tf = Kf * molality. Given that the molality of the solution is 4 moles NaCl per kg water and the Kf value for water is 1.86 °C/m, the decrease in freezing point would be approximately 7.44°C.
The freezing point decrease is -14,8 oC.
The freezing point of water decreases by about 1.86 degrees Celsius for each mole of solute (such as sugar) dissolved in 1 kg of water. So, the freezing point would decrease by 1.86 degrees Celsius for every mole of sugar added.
The normal freezing temperature for pure water is 0c. Howeverif sugar is added in the pure water, the freezing point will be lower than zero. How far below zero will depend on the sugar concentration in the water.
The melting point of ice decreases when salt is added.
The freezing point depression constant for water is 1.86°C kg/mol. With 4 moles of NaCl added to 1 kg of water, the molality would be 4 mol / 1 kg = 4 m. The freezing point depression can be calculated as 1.86°C kg/mol * 4 m = 7.44°C.
it lowers it. impurities lower the melting and raise the boiling point of substances. they also cause the melting point to fall over a range now. for example, water's melting point was initially 0 but upon adding salt it now is -5 to -1 degrees celsius.
This is a colligative property. Adding a solute will increase the boiling point and decrease the freezing point. The reason has to due with intermolecular forces, and interruption thereof. When water molecules have solute in between them, the temperature has to be lower than normal in order for them to freeze.
7.44 degrees c.
The freezing point of a solution decreases according to the formula: delta Tf = Kf * molality. Given that the molality of the solution is 4 moles NaCl per kg water and the Kf value for water is 1.86 °C/m, the decrease in freezing point would be approximately 7.44°C.
The freezing point depression constant for water is 1.86°C kg/mol. Using the formula ΔT = i * Kf * molality, where i is the van't Hoff factor (for NaCl, i = 2) and molality = moles of solute / kg of solvent, the freezing point of water would decrease by approximately 14.88°C.
Adding salt to water the freezing point decrease.
14.88 degrees Celsius.