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Beryllium sulfate is soluble in water.

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9y ago

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BaSO4 + 2H2O --> Ba(OH)2 + H2SO4 There is now one Barium, one Sulfate, two hydroxides, and two oxygens on either side of the arrow. The above reaction would make sense if barium sulfate was soluble in water... but it is not. In fact, it is so insoluble in water that there is no reaction.


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What solvent would separate BaSO4 and quinidine?

water because quinidine is water soluble, being an organic substance used in the body and dissolved by a glass of water taken with the medication, whereas BaSO4 is not water soluble at all


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What results from the dissociation of BaSO4?

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What is the simplest formula for 0.080 mole Ba and 0.080 mole S and 0.320 mole O?

The simplest formula based on the given moles would be BaSO4 (barium sulfate). This is determined by dividing each mole value by the smallest mole value (0.080 mole), resulting in a ratio of 1 Ba : 1 S : 4 O, which corresponds to BaSO4.