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aniline and phenol can form hydrogen bonds with water molecules through their -NH2 and -OH groups, while nitrobenzene has no available hydrogens, but in principle can form hydrogen bonds with its oxygens with water hydrogen.
As a matter of fact, the first option is more favorable than the second (e.g. butanol CH3CH2CH2CH2-OH is slightly more soluble than butanal CH3CH3CH2HC=0 in water, and the difference in solubility increases at increasing alkyl chain length).
On a qualitative basis, one can think that aniline and phenol are more similar to water than nitrobenzene, hence they are more miscible.

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Q: If Nitrobenzene has a larger dipole moment then aniline and phenol but is much less soluble in water?
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