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sodium hydroxide is prepared industrally by the electrolysis of brime but the lab. Preparation is sodium chloride and trioxosulphate(vi)acid.

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Is NaOH a radical?

No, NaOH is not a radical. It is a chemical compound called sodium hydroxide, which is an inorganic base commonly used in industrial and laboratory applications.


What is the important of NaOH in preparation of bromoaniline?

NaOH is important in the preparation of bromoaniline as it is used to deprotonate the aniline molecule, making it more nucleophilic. This allows the bromine atom to substitute for one hydrogen atom on the benzene ring to form bromoaniline. Additionally, NaOH helps to maintain the reaction conditions at a suitable pH for the substitution reaction to occur efficiently.


0.01N NAOH solution preparation?

To prepare a 0.01N NaOH solution, you would need to dissolve 0.4 grams of NaOH in 1 liter of water. Make sure to wear proper protective gear and use a glass stirring rod to dissolve the NaOH slowly in the water to prevent splattering. Measure and mix thoroughly to ensure uniformity of the solution before use.


What is the equation for the preparation of bleach?

The equation for the preparation of bleach is the reaction between sodium hydroxide (NaOH) and chlorine gas (Cl2), which forms sodium hypochlorite (NaOCl) and water (H2O). The balanced chemical equation is 2 NaOH + Cl2 → NaOCl + NaCl + H2O.


HOW TO 0.1N NaOH solution preparation?

To prepare a 0.1N NaOH solution, dissolve 4g of sodium hydroxide (NaOH) pellets in enough water to make 1 liter of solution. Use a volumetric flask to accurately measure the final volume. Remember to handle NaOH with caution as it is a caustic substance.

Related Questions

Is NaOH a radical?

No, NaOH is not a radical. It is a chemical compound called sodium hydroxide, which is an inorganic base commonly used in industrial and laboratory applications.


What is the important of NaOH in preparation of bromoaniline?

NaOH is important in the preparation of bromoaniline as it is used to deprotonate the aniline molecule, making it more nucleophilic. This allows the bromine atom to substitute for one hydrogen atom on the benzene ring to form bromoaniline. Additionally, NaOH helps to maintain the reaction conditions at a suitable pH for the substitution reaction to occur efficiently.


0.01N NAOH solution preparation?

To prepare a 0.01N NaOH solution, you would need to dissolve 0.4 grams of NaOH in 1 liter of water. Make sure to wear proper protective gear and use a glass stirring rod to dissolve the NaOH slowly in the water to prevent splattering. Measure and mix thoroughly to ensure uniformity of the solution before use.


What is the equation for the preparation of bleach?

The equation for the preparation of bleach is the reaction between sodium hydroxide (NaOH) and chlorine gas (Cl2), which forms sodium hypochlorite (NaOCl) and water (H2O). The balanced chemical equation is 2 NaOH + Cl2 → NaOCl + NaCl + H2O.


What is the name for the industrial preparation of iron?

the blast furnace


Preparation of laughing gas with diagram?

by gently heating NH4NO3


HOW TO 0.1N NaOH solution preparation?

To prepare a 0.1N NaOH solution, dissolve 4g of sodium hydroxide (NaOH) pellets in enough water to make 1 liter of solution. Use a volumetric flask to accurately measure the final volume. Remember to handle NaOH with caution as it is a caustic substance.


Experiment in acid base and salt?

An example; preparation of sodium chloride in laboratory: NaOH + HCl = NaCl + H2O


What is the chemical formula of caustic used in alumina preparation from bauxite in Bayer's process?

NaOH it is a concentrated form of sodium hydroxide


How do you get sodium chloride?

Two methods of preparation in laboratory:- 2 Na + Cl2 = 2 NaCl- NaOH + HCL = NaCl + H2O


How do you make salt scientifically?

Two methods for the preparation of salt in laboratory are: - 2Na + Cl2 = 2NaCl - NaOH + HCl = NaCl + H2O


What is salt's basic components and how is it created?

Sodium chloride (NaCl) contain sodium and chlorine: a laboratory method of preparation is: NaOH + HCl = NaCl + H2O