NaOH is important in the preparation of bromoaniline as it is used to deprotonate the aniline molecule, making it more nucleophilic. This allows the bromine atom to substitute for one hydrogen atom on the benzene ring to form bromoaniline. Additionally, NaOH helps to maintain the reaction conditions at a suitable pH for the substitution reaction to occur efficiently.
p-Bromoaniline can be prepared by the reaction of aniline with bromine in the presence of a catalyst like iron (III) chloride. The reaction proceeds through electrophilic aromatic substitution on the benzene ring, with bromine substituting the hydrogen at the para position to the amino group to yield p-bromoaniline. Purification can be done through recrystallization.
To prepare a 0.01N NaOH solution, you would need to dissolve 0.4 grams of NaOH in 1 liter of water. Make sure to wear proper protective gear and use a glass stirring rod to dissolve the NaOH slowly in the water to prevent splattering. Measure and mix thoroughly to ensure uniformity of the solution before use.
The equation for the preparation of bleach is the reaction between sodium hydroxide (NaOH) and chlorine gas (Cl2), which forms sodium hypochlorite (NaOCl) and water (H2O). The balanced chemical equation is 2 NaOH + Cl2 → NaOCl + NaCl + H2O.
The percentage yield of p-bromoaniline can be calculated by dividing the actual yield by the theoretical yield and multiplying by 100. The actual yield is the amount of p-bromoaniline obtained from the reaction, while the theoretical yield is the maximum amount that can be produced based on the reaction stoichiometry.
To prepare a 0.1N NaOH solution, dissolve 4g of sodium hydroxide (NaOH) pellets in enough water to make 1 liter of solution. Use a volumetric flask to accurately measure the final volume. Remember to handle NaOH with caution as it is a caustic substance.
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p-Bromoaniline can be prepared by the reaction of aniline with bromine in the presence of a catalyst like iron (III) chloride. The reaction proceeds through electrophilic aromatic substitution on the benzene ring, with bromine substituting the hydrogen at the para position to the amino group to yield p-bromoaniline. Purification can be done through recrystallization.
Sodium hydroxide is used in the preparation of bromoaniline as a base to deprotonate the aniline compound, making it more reactive towards the brominating reagent. This reaction typically involves a substitution of a hydrogen atom on the aniline molecule with a bromine atom. Sodium hydroxide helps facilitate this reaction by providing the necessary basic conditions for the deprotonation step.
To prepare a 0.01N NaOH solution, you would need to dissolve 0.4 grams of NaOH in 1 liter of water. Make sure to wear proper protective gear and use a glass stirring rod to dissolve the NaOH slowly in the water to prevent splattering. Measure and mix thoroughly to ensure uniformity of the solution before use.
The equation for the preparation of bleach is the reaction between sodium hydroxide (NaOH) and chlorine gas (Cl2), which forms sodium hypochlorite (NaOCl) and water (H2O). The balanced chemical equation is 2 NaOH + Cl2 → NaOCl + NaCl + H2O.
The percentage yield of p-bromoaniline can be calculated by dividing the actual yield by the theoretical yield and multiplying by 100. The actual yield is the amount of p-bromoaniline obtained from the reaction, while the theoretical yield is the maximum amount that can be produced based on the reaction stoichiometry.
To prepare a 0.1N NaOH solution, dissolve 4g of sodium hydroxide (NaOH) pellets in enough water to make 1 liter of solution. Use a volumetric flask to accurately measure the final volume. Remember to handle NaOH with caution as it is a caustic substance.
An example; preparation of sodium chloride in laboratory: NaOH + HCl = NaCl + H2O
4p+5o2->p4o10
4p+5o2->p4o10
Take p-bromoacetanilide in a round bottom flask n reflux it on a water bath using ethanol and HCl. Reflux it for around 30 minutes. Cool it in an ice bath and neutralise with 20% NaOH. Filter the separated p-bromoaniline.
NaOH it is a concentrated form of sodium hydroxide