I assume you mean 3y+2x+1. So sub in the points and see. The 1 is x and the -3 is y.
3(-3) + 2(1) + 1. Does this equal 0? -9+2+1 equals -6, so no, it is not a solution. For example, if your point is (1,-1), this would be a solution.Check what it is dissolved in first and use the same solvent for dilution. If you want to make a litre of 10% for instance, You want to dilute it 10 in 26 parts or 5 in 13. So 1 litre /13*5 is 384.6ml of 26% ammonia, and dilute to 1 litre with solvent
The oxidation number of carbon in C2H4O is +2, as each hydrogen has an oxidation number of +1 and each oxygen has an oxidation number of -2. By setting up the equation 2x + 4(+1) + 1(-2) = 0, you can solve for x to find the oxidation number of carbon.
The solution is acidic. A pH of 1 indicates a high concentration of H+ ions in the solution, making it strongly acidic.
To prepare 0.1N NaOH solution from a 1N NaOH solution, you can dilute 1 part of the 1N solution with 9 parts of water (since 1/10 = 0.1). Measure 1 volume of the 1N NaOH solution and add 9 volumes of water to it, then mix well to get your 0.1N NaOH solution.
Since pH is a logarithmic scale, each increase (or decrease) by 1 means 10 times, so the change of pH in a solution from 10 to 11 would be 10 times, 11 to 12 would be 10 times, and 12 to 13 would be 10 times, and (10)(10)(10) is 1000, so a solution with pH 13 is 1000 times more basic then a solution with pH 10
2x plus 3y
Yes if you mean (1, 3) and 3y = 2x+1
3(2x + 3y)(2x - 3y)
1) 2x + 1 = 3y 2) 4 = 3y - 10 this can be re-written as 3y = 4 + 10 Therefore 2x + 1 = 4 + 10 2x = 13 x = 6.5 Sustitute x = 6.5 in equation 1) above 2x + 1 = 3y 2 (6.5) + 1 = 3y therefore 3y = 13 +1 3y = 14 y = 14/3 Now substitute y = 14/3 in equation 2) above and watch what happens! 4 = 3(14/3) -10 4 = 4 Therefore the answer is correct!
2x + 5y = 16 -2x - 3y = -14 2y = 2 y = 1 / x = 5.5 (5.5,1) or (5 1/2,1)
To determine if an ordered pair ((x, y)) is a solution to the inequality (3y - 1 - 2x \geq 0), we can rearrange it to (3y \geq 2x + 1). For example, if we take the ordered pair ((1, 1)), we substitute (x = 1) and (y = 1): (3(1) \geq 2(1) + 1), which simplifies to (3 \geq 3). Since this is true, ((1, 1)) is a valid solution to the inequality.
2x + 3y = 1 y = 1/3 - 2x/3
-2x+3y=1 3y=1+2x y=(1+2x)/3 Then proceed to find points by plugging in given or arbitrary values of x.
-2x plus 3y equals 1
If you mean: 6x-3y = -33 and 2x+y = -1 Then solving the simultaneous equations by substitution: x = -3 and y = 5
2x - 3y = -1 3x + 2y = 31 eqn(1) * 2: 4x - 6y = -2 eqn(2) * 3: 9x + 6y = 93 Add the two: 13x = 91 Divide both sides by 13: x = 7 Substitute this value of x into eqn(1): 14 - 3y = -1 Add 3y to bot sides: 14 = -1 + 3y Add 1 to both sides: 15 = 3y Divide both sides by 3: 5 = y So the solution is x = 7, y = 5
Without any equality signs the given terms can't be considered to be equations.