NO!!!
In one molecule of NaCl there are TWO(2) ions ; Na^(+) & Cl^(-)
In one molecule of MgCl2 there are THREE(3) ions ; Mg^(2+) , Cl^(-) & Cl^(-) .
Hence it follows that in one mole of NaCl there are less ions than there are in one mole of MgCl2, by a ratio of 2:3 .
I assume that is 28.0 grams.28.0 grams MgCl2 (1 mole MgCl2/95.21 grams)= 0.294 moles magnesium chloride==========================Now,One mole Mg 2+ = 0.294 moles Mg 2+ ions=============================2 moles Cl - = 0.588 moles Cl - ions=========================
In the same volume of water, one mole of MgCl2 will give rise to a greater boiling point elevation. This is explained by the fact that boiling point elevation is a colligative property, that is, the relative amounts of the constituents are important and not their identity. We can determine by inspection that, upon dissociation, more ions will be produced by MgCl2 than NaCl since there are more atoms in the MgCl2 molecule. So, for one mole of MgCl2, we will produce one mole of magnesium and two of chlorine (three total). For one mole of NaCl, we produce one mole each of potassium and chlorine. By employing the principle stated above, we can come to the correct conclusion.
Magnesium (Mg) and chlorine (Cl) are the elements present in magnesium chloride (MgCl2). MgCl2 is an ionic compound consisting of one magnesium ion (Mg2+) and two chloride ions (Cl-).
MgCl2 is formed. Mg2+ + 2Cl- ----> MgCl2
When HCl dissociates, it produces 1 mole of H+ ions and 1 mole of Cl- ions for every mole of HCl. So, 1 mole of HCl will produce a total of 2 moles of ions (H+ and Cl-).
Two Chloride ions (2Cl-) ions are needed with their -1 charge on each one to cancel out the +2 charge of the single Magnesium ion (Mg2+). So Magnesium Chloride would have the chemical formula: MgCl2
No, 1 mole of NaCl will produce 2 ions (1 Na+ and 1 Cl-) while 1 mole of MgCl2 will produce 3 ions (1 Mg2+ and 2 Cl-), so they do not have an equal number of ions.
I assume that is 28.0 grams.28.0 grams MgCl2 (1 mole MgCl2/95.21 grams)= 0.294 moles magnesium chloride==========================Now,One mole Mg 2+ = 0.294 moles Mg 2+ ions=============================2 moles Cl - = 0.588 moles Cl - ions=========================
MgCl2 will dissolve in water to form magnesium ions (Mg2+) and chloride ions (Cl-) in solution.
In the same volume of water, one mole of MgCl2 will give rise to a greater boiling point elevation. This is explained by the fact that boiling point elevation is a colligative property, that is, the relative amounts of the constituents are important and not their identity. We can determine by inspection that, upon dissociation, more ions will be produced by MgCl2 than NaCl since there are more atoms in the MgCl2 molecule. So, for one mole of MgCl2, we will produce one mole of magnesium and two of chlorine (three total). For one mole of NaCl, we produce one mole each of potassium and chlorine. By employing the principle stated above, we can come to the correct conclusion.
Magnesium (Mg) and chlorine (Cl) are the elements present in magnesium chloride (MgCl2). MgCl2 is an ionic compound consisting of one magnesium ion (Mg2+) and two chloride ions (Cl-).
Yes, MgCl2 can form an aqueous solution when it is dissolved in water. MgCl2 dissociates into magnesium (Mg2+) ions and chloride (Cl-) ions in water, forming an aqueous solution.
MgCl2 is formed. Mg2+ + 2Cl- ----> MgCl2
When HCl dissociates, it produces 1 mole of H+ ions and 1 mole of Cl- ions for every mole of HCl. So, 1 mole of HCl will produce a total of 2 moles of ions (H+ and Cl-).
Yes, MgCl2 is a salt. It is composed of magnesium ions (Mg2+) and chloride ions (Cl-), which are bonded together through ionic bonds.
Based on the stoichiometry of NaCl, for every one mole of NaCl there is one mole of Na+ and one mole of Cl-. Therefore, there are 1.5 moles Na+ and 1.5 moles Cl-, totaling 3 moles of ions altogether
MgCl2 is soluble in water. It will dissociate into Mg2+ and Cl- ions when dissolved in water, forming a clear solution.