A mole is simply a number of particles (atoms, molecules, cats...anything) and it is equal to 6.023x10^23. So yes, 1 mole of NaCl will have 6.023x10^23 ions, and MgCl2 will have the same number of ions. However, the proportions of each ion will differ in each case.
I assume that is 28.0 grams.28.0 grams MgCl2 (1 mole MgCl2/95.21 grams)= 0.294 moles magnesium chloride==========================Now,One mole Mg 2+ = 0.294 moles Mg 2+ ions=============================2 moles Cl - = 0.588 moles Cl - ions=========================
My teacher has engraved this saying into my head: chemical formulas are mole ratios. Each compound is composed of elements and each molecule of a compound is created by the same ratio of elements. For example MgCl2 (Magnesium chloride). For every MgCl2 molecule, one Mg+2 ion and two Cl-1 ions come together to form MgCl2. This means that for every mole of MgCl2, it will be made up of 1 mole of Mg and 2 moles of Cl. The subscripts on the elements are the number of moles of each element used to create the compound, so it would be correct to say that the chemical formula is a ratio of moles of each of the elements in the compound.
Each molecule CoCl2 ionises in three single ions (1 Co2+ and 2 Cl- ions), so 0.27 mol CoCl2 gives 3 * 0.27 = 0.81 mole ions (0.27 mole Co2+ and 0.54 mole Cl- ions)
It does NOT form molecules. When AlCl3 'breakdown ' it form the IONS Al^(3+) & 3 Cl^(-) AlCl3(s) IS a molecule.
To determine the number of atoms in one mole of MgCl2 (magnesium chloride), you can use Avogadro's number, which is approximately 6.022 x 10^23 atoms/molecules per mole. First, you need to calculate the molar mass of MgCl2. Magnesium (Mg) has an atomic mass of approximately 24.31 g/mol. Chlorine (Cl) has an atomic mass of approximately 35.45 g/mol (rounded to two decimal places). Now, add the atomic masses of one magnesium atom and two chlorine atoms to find the molar mass of MgCl2: MgCl2 molar mass = (1 x Mg atomic mass) + (2 x Cl atomic mass) MgCl2 molar mass = (1 x 24.31 g/mol) + (2 x 35.45 g/mol) MgCl2 molar mass = 24.31 g/mol + 70.90 g/mol MgCl2 molar mass = 95.21 g/mol So, the molar mass of MgCl2 is approximately 95.21 g/mol. Now, using Avogadro's number, you can calculate the number of atoms in one mole of MgCl2: Number of atoms in 1 mole of MgCl2 = 6.022 x 10^23 atoms/molecules per mole Now, divide this by the molar mass of MgCl2 (95.21 g/mol): Number of atoms in 1 mole of MgCl2 = (6.022 x 10^23 atoms/mol) / (95.21 g/mol) Number of atoms in 1 mole of MgCl2 ≈ 6.32 x 10^21 atoms So, there are approximately 6.32 x 10^21 atoms in one mole of MgCl2.
Two Chloride ions (2Cl-) ions are needed with their -1 charge on each one to cancel out the +2 charge of the single Magnesium ion (Mg2+). So Magnesium Chloride would have the chemical formula: MgCl2
I assume that is 28.0 grams.28.0 grams MgCl2 (1 mole MgCl2/95.21 grams)= 0.294 moles magnesium chloride==========================Now,One mole Mg 2+ = 0.294 moles Mg 2+ ions=============================2 moles Cl - = 0.588 moles Cl - ions=========================
My teacher has engraved this saying into my head: chemical formulas are mole ratios. Each compound is composed of elements and each molecule of a compound is created by the same ratio of elements. For example MgCl2 (Magnesium chloride). For every MgCl2 molecule, one Mg+2 ion and two Cl-1 ions come together to form MgCl2. This means that for every mole of MgCl2, it will be made up of 1 mole of Mg and 2 moles of Cl. The subscripts on the elements are the number of moles of each element used to create the compound, so it would be correct to say that the chemical formula is a ratio of moles of each of the elements in the compound.
MgCl2 is an ionic compound with the Mg2+ cation and the Cl- anion in a 1:2 ratio. In each formula unit of MgCl2 there are two Mg2+ and one Cl- ion. So in 4 moles of MgCl2 there will be 12 moles of ions.
Each molecule CoCl2 ionises in three single ions (1 Co2+ and 2 Cl- ions), so 0.27 mol CoCl2 gives 3 * 0.27 = 0.81 mole ions (0.27 mole Co2+ and 0.54 mole Cl- ions)
One mole of chloride (Cl-) to one mole of Ag+ ions: Cl- + Ag+ --> AgCl(s)
The osmotic pressure depends on the number of dissolved particles in solution. When you dissolve one mole of sugar molecules, the result is one mole of dissolved particles. When you dissolve sugar, or sodium chloride (NaCl), the salt breaks apart into two ions, Na+ and Cl-. So when you dissolve one mole of salt, you have two moles of particles in solution. If you used something like magnesium chloride, MgCl2, you'd get 3 moles of particles for each mole of MgCl2 -- one mole of Mg2+ and 2 moles of Cl-.See the Web Links for more information.
Based on the stoichiometry of NaCl, for every one mole of NaCl there is one mole of Na+ and one mole of Cl-. Therefore, there are 2.5 moles Na+ and 2.5 moles Cl-, totaling 5 moles of ions altogether.
Based on the stoichiometry of NaCl, for every one mole of NaCl there is one mole of Na+ and one mole of Cl-. Therefore, there are 1.5 moles Na+ and 1.5 moles Cl-, totaling 3 moles of ions altogether
It does NOT form molecules. When AlCl3 'breakdown ' it form the IONS Al^(3+) & 3 Cl^(-) AlCl3(s) IS a molecule.
Mg2+ + 2 Cl- are in 1 : 2 ratio (of ions) so also 0.25 : 0.50 mole ratio
In MgCl2 magnesium has +2 valence and chlorine has -1 valence. Since the molecule' tends to be neutral two (-1) charged Cl-ions combine with one (+2) Mg2+ion.