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Yes it is molecular (or covalent) compound

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12y ago

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What is the molecular geometry shape of CBr4?

Tetrahedral


Is CBr4 ionic or molecular?

CBr4 is a molecular compound because it consists of nonmetallic elements (carbon and bromine) bonded together through covalent bonds. Ionic compounds typically form between a metal and a nonmetal, with electrons being transferred rather than shared.


How many molecules are in 393g of CBr4?

The molecular mass of CBr4 is 12.0 + 4(79.9) = 331.6Amount of CBr4 = mass of substance / molecular mass = 393/331.6 = 1.19mol This means that a 393g pure sample contains 1.19 moles of tetrabromomethane. The Avogadro's number is 6.02 x 10^23 So, number of molecules of CBr4 = 1.19 x 6.02 x 10^23 = 7.13 x 10^23


What is the number of lone pairs around the central atom and the molecular geometry of CBr4?

There are no lone pairs and it's tetrahedral.


How much viscosity in cf4 ccl4 and cbr4?

CF4 has the lowest viscosity, followed by CCl4, and then CBr4. This is because viscosity is generally higher for heavier molecules due to stronger intermolecular forces that inhibit molecular motion.


What is the symbol for CBr4?

CBr4 , this is the correct formula for carbon-tetra-bromide


How many ATOMS of carbon are present in 4.25 moles of carbon tetrabromide?

There are 1.03 x 10^24 atoms of carbon in 4.25 moles of carbon tetrabromide (CBr4). This can be calculated by multiplying Avogadro's number (6.022 x 10^23) by the number of moles of carbon in CBr4 (4).


What is the molecular geometry for CBr4?

whenever carbon atom forms four covalent bonds the basic structure is tetrahedral because carbon in such cases is sp3 hybridized.


Will CBr4 and H2O form homogeneous solutions when combined?

No, CBr4 and H2O will not form a homogeneous solution. CBr4 is a nonpolar compound, while H2O is polar. Due to the significant difference in polarity, they will not mix evenly to form a homogeneous solution.


Is CBr4 metal or non-metal?

Yes


Formula for carbon tetrabromide?

CBr4


How many molecules are in 325g of CBr4?

To find the number of molecules in 325g of CBr4, first calculate the number of moles using the molar mass of CBr4 (331.63 g/mol). Then, use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules. So, 325g of CBr4 is equal to about 0.981 moles, which is approximately 5.91 x 10^23 molecules.