Yes it is molecular (or covalent) compound
CF4 has the lowest viscosity, followed by CCl4, and then CBr4. This is because viscosity is generally higher for heavier molecules due to stronger intermolecular forces that inhibit molecular motion.
No, CBr4 and H2O will not form a homogeneous solution. CBr4 is a nonpolar compound, while H2O is polar. Due to the significant difference in polarity, they will not mix evenly to form a homogeneous solution.
Yes
To find the number of molecules in 325g of CBr4, first calculate the number of moles using the molar mass of CBr4 (331.63 g/mol). Then, use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules. So, 325g of CBr4 is equal to about 0.981 moles, which is approximately 5.91 x 10^23 molecules.
No, tetrabromomethane (CBr4) is a covalent compound, not ionic. It is composed of nonmetal elements (carbon and bromine) that share electrons to form covalent bonds.
Tetrahedral
CBr4 is a molecular compound because it consists of nonmetallic elements (carbon and bromine) bonded together through covalent bonds. Ionic compounds typically form between a metal and a nonmetal, with electrons being transferred rather than shared.
The molecular mass of CBr4 is 12.0 + 4(79.9) = 331.6Amount of CBr4 = mass of substance / molecular mass = 393/331.6 = 1.19mol This means that a 393g pure sample contains 1.19 moles of tetrabromomethane. The Avogadro's number is 6.02 x 10^23 So, number of molecules of CBr4 = 1.19 x 6.02 x 10^23 = 7.13 x 10^23
There are no lone pairs and it's tetrahedral.
CF4 has the lowest viscosity, followed by CCl4, and then CBr4. This is because viscosity is generally higher for heavier molecules due to stronger intermolecular forces that inhibit molecular motion.
CBr4 , this is the correct formula for carbon-tetra-bromide
There are 1.03 x 10^24 atoms of carbon in 4.25 moles of carbon tetrabromide (CBr4). This can be calculated by multiplying Avogadro's number (6.022 x 10^23) by the number of moles of carbon in CBr4 (4).
whenever carbon atom forms four covalent bonds the basic structure is tetrahedral because carbon in such cases is sp3 hybridized.
No, CBr4 and H2O will not form a homogeneous solution. CBr4 is a nonpolar compound, while H2O is polar. Due to the significant difference in polarity, they will not mix evenly to form a homogeneous solution.
Yes
CBr4
To find the number of molecules in 325g of CBr4, first calculate the number of moles using the molar mass of CBr4 (331.63 g/mol). Then, use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules. So, 325g of CBr4 is equal to about 0.981 moles, which is approximately 5.91 x 10^23 molecules.